python之tensorflow : Shape mismatch issue with one dimensional data

我试图将 x_data 作为 feed_dict 传递，但出现以下错误，我不确定代码中有什么问题。

InvalidArgumentError (see above for traceback): You must feed a value for placeholder tensor 'x_12' with dtype int32 and shape [1000] 
     [[Node: x_12 = Placeholder[dtype=DT_INT32, shape=[1000], _device="/job:localhost/replica:0/task:0/cpu:0"]()]] 

我的代码:

import tensorflow as tf 
import numpy as np 
model = tf.global_variables_initializer() 
#define x and y 
x = tf.placeholder(shape=[1000],dtype=tf.int32,name="x") 
y = tf.Variable(5*x**2-3*x+15,name = "y") 
x_data = tf.pack(np.random.randint(0,100,size=1000)) 
print(x_data) 
print(x) 
with tf.Session() as sess: 
    sess.run(model) 
    print(sess.run(y,feed_dict={x:x_data})) 

我检查了 x 和 x_data 的形状，它们是一样的

Tensor("pack_8:0", shape=(1000,), dtype=int32) 
Tensor("x_14:0", shape=(1000,), dtype=int32) 

我正在处理一维数据。 感谢任何帮助，谢谢!

请您参考如下方法:

为了让它工作，我改变了两件事，首先我将 y 更改为 Tensor。其次，我没有将 x_data 更改为 Tensor，如评论 here :

The optional feed_dict argument allows the caller to override the value of tensors in the graph. Each key in feed_dict can be one of the following types:

If the key is a Tensor, the value may be a Python scalar, string, list, or numpy ndarray that can be converted to the same dtype as that tensor. Additionally, if the key is a placeholder, the shape of the value will be checked for compatibility with the placeholder.

对我有用的更改代码:

import tensorflow as tf 
import numpy as np 
model = tf.global_variables_initializer() 
#define x and y 
x = tf.placeholder(shape=[1000],dtype=tf.int32,name="x") 
y = 5*x**2-3*x+15 # without tf.Variable, making it a tf.Tensor 
x_data = np.random.randint(0,100,size=1000) # without tf.pack 
print(x_data) 
print(x) 
with tf.Session() as sess: 
    sess.run(model) 
    print(sess.run(y,feed_dict={x:x_data}))