jquery之使用ajax和django传递信息

我正在尝试使用 Django View 测试 ajax 的使用。我是 ajax 和 django 的新手。我创建了一个由 3*3 个按钮单元格组成的网格。当我单击任何按钮时，它会将其文本替换为和“X”，然后应该在 ajax 的帮助下传递给查看“处理程序”。但在我的例子中，它并没有传递控制权来查看“处理程序”。我不明白为什么它不起作用。 这是我的代码:

网址文件:

 from django.conf.urls import include, url 
    from django.contrib import admin 
    from game import views 
    urlpatterns = [ 
        url(r'^admin/', admin.site.urls), 
        url(r'^handler/',views.handler,name='handler'), 
        url(r'^$',views.home,name='home'), 
    ] 

查看文件

from django.shortcuts import render 
    from django.http import HttpResponse 
    from django.http import Http404 
 
    def handler(request): 
        if request.is_ajax(): 
            pos = request.POST['pos'] 
            return HttpResponse(2) 
        else: 
            raise Http404 
    def home(request): 
        context = {} 
        return render(request,"game/home.html",context) 

home.html 文件:

<head> 
<head> 
<style> 
td { 
    padding:0; 
} 
table { 
    height:240px; 
    width:240px; 
    border-collapse: collapse; 
    border-spacing: 0 
} 
input { 
    margin:0; 
    width:80px; 
    height:80px; 
    font-size: 50px; 
    text-align: center; 
} 
#content { 
    position:absolute; 
    top:210px; 
    left:540px; 
} 
</style> 
<script> 
function change(id) 
{ 
    var y = document.getElementById(id); 
    y.value = 'X'; 
    $.ajax({ 
        url:"handler/", 
        type:"POST", 
        data:{pos:id}, 
 
        success:function(data) { 
            var x = document.getElementById(data); 
            x.value = 'O'; 
            console.log("sucess"); 
        }, 
        error:function(xhr,errmsg,err) { 
            alert("error"); 
        } 
    }); 
} 
</script> 
</head> 
<body> 
<div id = "content"> 
<center><table> 
<tr> 
<td><input type = "button" onclick="change(1)" id = "1"></input></td> 
<td><input type = "button" onclick="change(2)" id = "2"></input></td> 
<td><input type = "button" onclick="change(3)" id = "3"></input></td> 
</tr> 
<tr> 
<td><input type = "button" onclick="change(4)" id = "4"></input></td> 
<td><input type = "button" onclick="change(5)" id = "5"></input></td> 
<td><input type = "button" onclick="change(6)" id = "6"></input></td> 
</tr> 
<tr> 
<td><input type = "button" onclick="change(7)" id = "7"></input></td> 
<td><input type = "button" onclick="change(8)" id = "8"></input></td> 
<td><input type = "button" onclick="change(9)" id = "9"></input></td> 
</tr> 
</table> 
</center> 
</div> 
</body> 
</html> 

请您参考如下方法:

使用 csrf_exempt 装饰器，因为您不通过 ajax 发送 csrf token 。此外，请确保您已包含 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>到你的模板文件中。这应该有效。

from django.views.decorators.csrf import csrf_exempt 
from django.shortcuts import render 
from django.http import HttpResponse 
from django.http import Http404 
 
@csrf_exempt 
def handler(request): 
    if request.is_ajax(): 
        pos = request.POST['pos'] 
        return HttpResponse(2) 
    else: 
        raise Http404