我正在尝试将 Django 和 Django REST Framework 混合到一个模块中,看看它是否可以工作。到目前为止,我有以下代码:
###############################################################################
# SETTINGS
###############################################################################
import os
from django.apps import apps
from django.conf import settings
BASE_DIR = os.path.dirname(os.path.dirname(os.path.dirname(__file__)))
if not settings.configured:
settings.configure(
DEBUG=True,
SECRET_KEY='thisisthesecretkey',
ROOT_URLCONF=__name__,
STATIC_URL='/static/',
STATICFILES_DIRS=(
os.path.join(BASE_DIR, "static"),
),
MIGRATION_MODULES = {'__main__': 'migrations'},
MIDDLEWARE_CLASSES=(
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
),
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3',
'NAME': 'tinydb',
}
},
INSTALLED_APPS = (
'__main__',
'rest_framework',
'django.contrib.staticfiles',
),
)
apps.populate(settings.INSTALLED_APPS)
###############################################################################
# MODELS
###############################################################################
from django.db import models
class Book(models.Model):
ISBN = models.AutoField(primary_key=True)
author = models.CharField(max_length=100)
title = models.CharField(max_length=200)
description = models.CharField(max_length=500)
###############################################################################
# SERIALIZERS
###############################################################################
from rest_framework import serializers
class BookSerializer(serializers.ModelSerializer):
class Meta:
model = Book
###############################################################################
# VIEWS
###############################################################################
class BooksView():
queryset = Book.objects.all()
serializer_class = BookSerializer
###############################################################################
# URLCONF
###############################################################################
from django.conf.urls import url, include
from rest_framework.routers import DefaultRouter
router = DefaultRouter()
router.register(r'books', BooksView)
urlpatterns = (
url(r'^$', include(router.urls)),
)
###############################################################################
# MANAGE
###############################################################################
import sys
if __name__ == "__main__":
from django.core.management import execute_from_command_line
execute_from_command_line(sys.argv)
现在,服务器正在运行,我看到了 API 浏览器。然而,当我尝试创建一个对象时,我得到了以下痕迹:
>>> from __main__ import Book
>>> Book.objects.create(author='a1', title='t1', description='d1')
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/manager.py", line 127, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/query.py", line 348, in create
obj.save(force_insert=True, using=self.db)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/base.py", line 734, in save
force_update=force_update, update_fields=update_fields)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/base.py", line 762, in save_base
updated = self._save_table(raw, cls, force_insert, force_update, using, update_fields)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/base.py", line 846, in _save_table
result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/base.py", line 885, in _do_insert
using=using, raw=raw)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/manager.py", line 127, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/query.py", line 920, in _insert
return query.get_compiler(using=using).execute_sql(return_id)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/models/sql/compiler.py", line 974, in execute_sql
cursor.execute(sql, params)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/backends/utils.py", line 79, in execute
return super(CursorDebugWrapper, self).execute(sql, params)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/utils.py", line 97, in __exit__
six.reraise(dj_exc_type, dj_exc_value, traceback)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/utils/six.py", line 658, in reraise
raise value.with_traceback(tb)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/home/lwm/.virtualenvs/tiny-api/lib/python3.4/site-packages/django/db/backends/sqlite3/base.py", line 318, in execute
return Database.Cursor.execute(self, query, params)
django.db.utils.OperationalError: no such table: __main___book
makemigrations 返回:
lwm$ python api.py makemigrations
No changes detected
我可以运行迁移:
lwm$ python api.py migrate
Operations to perform:
Synchronize unmigrated apps: __main__, staticfiles, rest_framework
Apply all migrations: (none)
Synchronizing apps without migrations:
Creating tables...
Running deferred SQL...
Installing custom SQL...
Running migrations:
No migrations to apply.
所以。我想,由于我的 Book 模型没有放在单独的应用程序中,因此没有为它创建数据库表。除了手动创建表(例如,使用 db_table 元字段)之外,我仍然希望获得 ORM 为我做事的所有好处。
有什么想法吗?
请您参考如下方法:
尝试从已安装的应用程序列表中删除 __main__。除非您实际上有一个名为 __main__ 的应用程序(考虑到 double underscores means something in python ,您可能不应该这样做),否则它不应该存在。
