python之在 Django 中，如何在 slug 标题中添加 id

如何在 slug 中添加 id，使其看起来像这样

"this-is-a-deal-1"

“这是一笔交易”是标题，“1”是 ID 号。目前，当前代码显示为 "this-is-a-deal-None"

模型.py ... slug = models.SlugField()

    def save(self, *args, **kwargs): 
        if not self.id: 
            # Newly created object, so set slug 
            self.slug = '%s-%s' %( 
                            slugify(self.deal_title), 
                            str(self.id)) 

View .py

def deal_page(request, deal_title_slug): 
 
    # Create a context dictionary which we can pass to the template rendering engine. 
    context_dict = {} 
 
    try: 
        deal = SubmitDeal.objects.get(slug=deal_title_slug) 
        context_dict['deal_title'] = deal.deal_title 
 
        context_dict['deal'] = deal 
    except SubmitDeal.DoesNotExist: 
        # We get here if we didn't find the specified category. 
        # Don't do anything - the template displays the "no category" message for us. 
        pass 
 
    return render(request, 'deal_page.html', context_dict) 

网址.py

url(r'^(?P<deal_title_slug>[\w\-]+)/$', 'submit_deals.views.deal_page', name='deal_page'), 

管理员.py

class SubmitModelAdmin(admin.ModelAdmin): 
    prepopulated_fields = {'slug':('deal_title',)} #prepopulate slug with deal_title 
    class meta: 
        model = SubmitDeal 
 
admin.site.register(SubmitDeal, SubmitModelAdmin) 

请您参考如下方法:

你不应该改变数据库中的 slug。将url中的slug和id分开:

url(r'^(?P<slug>[\w\-]+)-(?P<pk>\d+)/$', 'submit_deals.views.deal_page', 
                                         name='deal_page'), 

然后使用pk 获取对象并忽略slug:

def deal_page(request, slug, pk): 
    try: 
        deal = SubmitDeal.objects.get(pk=pk) 
        context_dict = {'deal_title': deal.deal_title, 'deal': deal} 
    except SubmitDeal.DoesNotExist: 
        context_dict = {} 
   return render(request, 'deal_page.html', context_dict)