Python 3 删除空列表

我正在从 10 行的文本中找到一行。

desc    = re.findall(r'@description (.*)', comment.strip()) 

发生的是它返回 @description 但它也有 9 个空列表。

print(desc) 

返回:

[] 
[] 
[] 
[] 
[] 
[] 
[] 
[] 
['the desc is here'] 
[] 

那么如何摆脱那些空的 [] 并使 desc=['the desc is here']？

---

更新

我试过列表过滤器，结果还是一样

评论包含:

/** 
 * @param string username   required    the username of the registering user  
 * @param string password   required 
 * @param string first_name required 
 * @param string last_name  required 
 * @param string email      required 
 * @package authentication 
 * @info user registration 
 * @description register a new user into the groupjump platform 
 */ 

---

更新

comment是一个完整的字符串，所以我把它拆分成这样，这样我就可以逐行阅读

comments = route['comment'] 
comments = list(filter(None, comments.split('\n'))) 

---

实际代码

#!/usr/bin/env python3 
 
import re 
 
routes = [] 
description = '' 
with open('troutes.php', 'r') as f: 
    current_comment = '' 
    in_comment = False 
    for line in f: 
        line = line.lstrip() 
        if line.startswith('/**'): 
            in_comment = True 
 
        if in_comment: 
            current_comment += line 
 
        if line.startswith('*/'): 
            in_comment = False 
 
        if line.startswith('Route::'): 
            matches = re.search(r"Route::([A-Z]+)\('(.*)', '(.*)'\);", line) 
            groups = matches.groups() 
            routes.append({ 
                'comment': current_comment, 
                'method': groups[0], 
                'path': groups[1], 
                'handler': groups[2], 
            }); 
            current_comment = '' # reset the comment 
 
for route in routes: 
 
  # get comments 
  comments = route['comment'] 
  comments = list(filter(None, comments.split('\n'))) 
 
  for comment in comments: 
    params  = re.findall(r'@param (.*)', comment.strip()) 
    object  = re.findall(r'@package (.*)', comment.strip()) 
    info    = re.findall(r'@info (.*)', comment.strip()) 
    desc    = re.search(r'@description (.*)', comment.strip()) 
 
    print(comment[15:]) 

正在读取的数据:

<?php 
/** 
 * @param string username   required    the username of the registering user  
 * @param string password   required 
 * @param string first_name required 
 * @param string last_name  required 
 * @param string email      required 
 * @package authentication 
 * @info user registration 
 * @description register a new user into the groupjump platform 
 */ 
Route::POST('v3/register', 'UserController@Register'); 
 
/** 
 * @param string username   required    the username of the registering user  
 * @param string password   required 
 */ 
Route::GET('v3/login', 'UserController@login'); 

请您参考如下方法:

单个列表的条件是:

if desc: 
    print(desc) 

它是以下内容的简写版本:

if len(desc) > 0: 
    print(desc) 

对于列表的列表，它是:

desc = [d for d in desc if d] 

要仅获取字符串，请执行以下操作:

if desc: 
    print(desc[0])