python之当 turtle 到达某个点时停止 turtle ，Python

我目前正在上初级编程课，正在完成作业。现在，我必须用模块 turtle build 3 个房子(我完成了):

def drawBody(mover): 
    #Rectangle part 
    mover.fillcolor("blue") 
    mover.begin_fill() 
    for i in range(2): 
        mover.forward(100) 
        mover.right(90) 
        mover.forward(75) 
        mover.right(90) 
    mover.end_fill() 
 
 
    #Triangle part 
    mover.fillcolor("red") 
    mover.begin_fill() 
    mover.left(45) 
    for i in range(2): 
        mover.forward(70.5) 
        mover.right(90) 
    mover.right(45) 
    mover.forward(100) 
    mover.end_fill() 
 
 
 
 
 
 
 
#Create preproduction turtle 
import turtle 
wn = turtle.Screen() 
josh = turtle.Turtle() 
 
 
pointGoTo = -175 
for houses in range(3): 
    josh.penup() 
    josh.goto(pointGoTo,0) 
    josh.pendown() 
 
    drawBody(josh) 
 
 
    josh.right(180) 
    pointGoTo = pointGoTo + 125 
 
wn.exitonclick() 

这是 while 代码。所以我想让 turtle 停在某个点，红色方 block 的左上角。我已经尝试了多个点，但只是没有中断/停止。我的语法关闭了吗？还是我处理整条房子的事情都错了？如果我含糊不清，请问你有什么不明白的，我真的很想弄清楚，但我完全没有想法。:

def drawBody(mover): 
    #Rectangle part 
    mover.fillcolor("blue") 
    mover.begin_fill() 
    for i in range(2): 
        mover.forward(100) 
        mover.right(90) 
        mover.forward(75) 
        mover.right(90) 
    mover.end_fill() 
 
 
    #Triangle part 
    mover.fillcolor("red") 
    mover.begin_fill() 
    mover.left(45) 
    for i in range(2): 
        mover.forward(70.5) 
        mover.right(90) 
    mover.right(45) 
    mover.forward(100) 
    mover.end_fill() 
 
    mover.left(90) 
    mover.forward(75) 
    mover.left(90) 
    n = mover.position() 
    print(n) 
    while True: 
        mover.forward(100) 
        n = mover.position() 
        print(n) 
        mover.left(90) 
        mover.forward(5) 
        mover.left(90) 
        n = mover.position() 
        print(n) 
        mover.forward(100) 
        mover.right(90) 
        mover.forward(5) 
        mover.right(90) 
 
 
        if n == (-75.30,0.00): 
            break 
 
 
 
 
 
 
 
#Create preproduction turtle 
import turtle 
wn = turtle.Screen() 
josh = turtle.Turtle() 
 
 
pointGoTo = -175 
for houses in range(3): 
    josh.penup() 
    josh.goto(pointGoTo,0) 
    josh.pendown() 
 
    drawBody(josh) 
 
 
    josh.right(180) 
    pointGoTo = pointGoTo + 125 
 
wn.exitonclick() 

请您参考如下方法:

首先，你检查错了地方，你必须在这里检查:

while True: 
    mover.forward(100) 
 
    mover.left(90) 
    mover.forward(5) 
    mover.left(90) 
    n = mover.position() 
 
    if abs(n - (-75.30, 0.00)) < 0.01: 
        break 
 
    mover.forward(100) 
    mover.right(90) 
    mover.forward(5) 
    mover.right(90) 

您的检查不成功，因为 n 实际上是 turtle.Vec2D ，并且坐标是 float ，你可以通过print n[0], n[1]看到。 SO 上有很多关于比较 float 的链接，比如 Testing floating point equality ， 例如。在您的情况下，您可以:

if abs(n - (-75.30, 0.00)) < 0.01: 
    break 

但我认为，对您来说最好的方法是只绘制固定次数:

mover.left(90) 
mover.forward(70) 
mover.left(90) 
for i in xrange(7): 
    mover.forward(100) 
    mover.left(90) 
    mover.forward(5) 
    mover.left(90) 
 
    mover.forward(100) 
    mover.right(90) 
    mover.forward(5) 
    mover.right(90) 

您还必须像这样更改您的代码:

for houses in range(3): 
    josh.penup() 
    josh.goto(pointGoTo,0) 
    josh.pendown() 
 
    drawBody(josh) 
 
    pointGoTo = pointGoTo + 125