尝试从 csv 文件中获取数据 这是我的 csv 文件的样子:
a,0,b,2,c,6,G,4,l,6,mi,2,m,0,s,4
a,2,b,2,c,0,G,4,l,6,mi,4,m,0,s,6
a,4,b,2,c,6,G,6,l,2,mi,4,m,0,s,0
a,2,b,0,c,2,G,6,l,4,mi,4,m,0,s,6
a,2,b,2,c,6,G,4,l,0,mi,6,m,0,s,4
a,2,b,6,c,0,G,6,l,0,mi,4,m,2,s,4
a,0,b,6,c,4,G,2,l,0,mi,6,m,4,s,2
a,6,b,6,c,4,G,0,l,0,mi,2,m,4,s,2
因此，例如在行 [0] 中， 取决于第1,3,5,7,9,11,13,15行中的数值 我需要获取 0,2,4,6,10,12,14
更深层次的例子: 从第 1 行开始: 我需要得到
a,m = 0
b,mi = 2
c,l = 6
G,s =4
最后，我要补充一下，哪两个的组合最高。所以本质上是每个的总和。
为了做到这一点:
# Sanitize filelist to keep only *.csv files
def sanitize_filelist(filelist):
sanitized_filelist = []
# Keep only the log file
for file in range(len(filelist)):
if string.lower(filelist[file][-4:]) == '.csv':
sanitized_filelist += [filelist[file]]
# print sanitized_filelist
return sanitized_filelist
def parse_files(dataset_path,file):
threads = [0,2,4,6,10,12,14]
coreid = [1,3,5,7,9,11,13,15]
cores = [0,2,4,6]
thread_data = [[],[],[],[],[],[],[]]
#core = [[],[],[],[],[],[],[]]
threadcorecount = [[0 for a in range(0,4)] for b in range(0,8)]
dataset = csv.reader(open(dataset_path, 'rb'), delimiter=',')
for line in dataset:
#print line
for thread in range(len(threads)):
thread_data[thread] = line[threads[thread]]
for core in range(len(threads)):
if line[coreid[core]] == cores[0]:
sub = core - 1
print thread_data[sub],cores[0]
我写了这个片段 - 仍然是一个测试版本。 我无法获取这些值并进行打印。没有错误..我不明白错误是什么。
请您参考如下方法:
如果我理解了您的所有请求，下面的代码应该可以解决问题:如果您想访问每一行中的值(或保存 counter 变量)和 sorted_results 来获取可能排列的计数。
一些引用:
- lambda functions (现在替换为更长的代码)
- Counter class
- sort dictionary by value (用于 sorted_results)
- operator module (用于 sorted_results)
代码如下:
import csv
from collections import Counter
import operator
def parse_files(dataset_path,f): # please avoid using reserved words like file
threads = range(0,16,2)
dataset = csv.reader(open(dataset_path,'rb'), delimiter=',')
results = []
for line in dataset:
counter = {str(x):[] for x in range(0,8,2)}
# map(lambda x:counter[line[x+1]].append(line[x]), threads)
# map(lambda ...) is just a more pythonic way to write the following two lines
for index in threads:
counter[line[index+1]].append(line[index])
# now counter is something like
#{'0': ['c', 'l'], '2': ['a', 'm'], '4': ['mi', 's'], '6': ['b', 'G']}
results.extend([','.join(v)+'='+k for k,v in counter.items()])
# in results, I'm appending something like this:
# {'c,l=6', 'a,m=0', 'b,mi=2', 'G,s=4'}
sorted_results = sorted(dict(Counter(results)).iteritems(), key=operator.itemgetter(1), reverse=True)
print '\n'.join(['The couple %s appears %d times'%el for el in sorted_results])
# >>> The couple a,b=2 appears 2 times
# >>> The couple c,m=4 appears 2 times
# >>> The couple G,s=4 appears 2 times
# >>> The couple c,mi=6 appears 1 times
# >>> The couple a,m=2 appears 1 times
# >>> ...
