python之在 python 中处理 SOAP 类型异常的最佳方法是什么

如果用户输入的数据不在 WSDL 访问的 Web 服务器上，我会得到一个错误:

<?xml version="1.0" encoding="UTF-8"?> 
<SOAP-ENV:Envelope xmlns:ns3="http://www.w3.org/2001/XMLSchema" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns0="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://soap.rpc.jira.atlassian.com" xmlns:ns2="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"> 
   <SOAP-ENV:Header/> 
   <ns2:Body> 
      <ns1:getFieldsForEdit> 
         <in0 xsi:type="ns3:string">FmofSimScl</in0> 
         <in1 xsi:type="ns3:string">QA-65000</in1> 
      </ns1:getFieldsForEdit> 
   </ns2:Body> 
</SOAP-ENV:Envelope> 
<?xml version="1.0" encoding="UTF-8"?> 
<SOAP-ENV:Envelope xmlns:ns3="http://www.w3.org/2001/XMLSchema" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns0="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://soap.rpc.jira.atlassian.com" xmlns:ns2="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"> 
   <SOAP-ENV:Header/> 
   <ns2:Body> 
      <ns1:getIssue> 
         <in0 xsi:type="ns3:string">FmofSimScl</in0> 
         <in1 xsi:type="ns3:string">QA-65000</in1> 
      </ns1:getIssue> 
   </ns2:Body> 
</SOAP-ENV:Envelope> 
Traceback (most recent call last): 
  File "/home/qa/jira-test/.hg/check_jira.py", line 64, in <module> 
    main() 
  File "/home/qa/jira-test/.hg/check_jira.py", line 12, in main 
    commit_text_verified = verify_commit_text(os.popen('hg tip --template "{desc}"')) 
  File "/home/qa/jira-test/.hg/check_jira.py", line 35, in verify_commit_text 
    if CheckForJiraIssueRecord(m_args) == 0: 
  File "/home/qa/jira-test/.hg/check_jira.py", line 58, in CheckForJiraIssueRecord 
    issue = com.run(command_name, logger, jira_env, my_args) 
  File "/home/qa/jira-test/.hg/jira.py", line 1367, in run 
    return self.commands[command].dispatch(logger, jira_env, args) 
  File "/home/qa/jira-test/.hg/jira.py", line 75, in dispatch 
    results = self.run(logger, jira_env, args) 
  File "/home/qa/jira-test/.hg/jira.py", line 174, in run 
    logger.error(decode(e)) 
  File "/home/qa/jira-test/.hg/jira.py", line 1434, in decode 
    str = e.faultstring 
AttributeError: 'WebFault' object has no attribute 'faultstring' 
transaction abort! 
rollback completed 
abort: pretxncommit.jira hook exited with status 1 

有没有办法处理这个问题，这样我就可以编写自己的错误字符串或警告消息来代替所有这些。如果我关闭标准输出，我不会得到 xml 数据，但我仍然会得到:

transaction abort! 
rollback completed 
abort: pretxncommit.jira hook exited with status 1 

which is from mercurial, but would be nice to have a an error string appended to it like warnings.warn("%s does not exist"%issue_id)

ok, i looked in jira.py and changed on line 1434 : str = e.faultstring to str = e.fault

and got:

faultcode = "soapenv:Server.userException" 
   faultstring = "com.atlassian.jira.rpc.exception.RemotePermissionException: This issue does not exist or you don't have permission to view it." 
   detail =  
      (detail){ 
         com.atlassian.jira.rpc.exception.RemotePermissionException = "" 
         hostname = "JIRA" 
      } 
 } 

请您参考如下方法:

它已在 jira.py 中修复: 将解码函数更改为:

 
def decode(e): 
    """Process an exception for useful feedback""" 
    # TODO how to log the fact it is an error, but allow info to be unchanged? 
    # TODO now fault not faultstring? 
    # The faultType class has faultcode, faultstring and detail 
    str = e.fault 
    if str == 'com.atlassian.jira.rpc.exception.RemotePermissionException': 
        return "This issue does not exist or you don't have permission to view it" 
    return e.fault 

代替:

 
def decode(e): 
    """Process an exception for useful feedback""" 
    # TODO how to log the fact it is an error, but allow info to be unchanged? 
    # TODO now fault not faultstring? 
    # The faultType class has faultcode, faultstring and detail 
    str = e.faultstring 
    if str == 'java.lang.NullPointerException': 
        return "Invalid issue key?" 
    return e.faultstring