我目前正在为一款游戏开发已发布的机器人，希望能学习更多关于编程的知识。不幸的是，当我进入二进制数组的主题时，我添加的一个起初看起来很简单的新命令变得非常困难。基本上，我采用了一个已经制定的命令，您可以在其中将一个项目放置在两个位置，以定义您将要恢复的区域。我对该命令的编辑是，它将允许完全恢复整个 map ，而无需放置任何项目来定义 map 。
在执行恢复命令之前，先执行备份命令，其中二进制数组由整个 map 组成，然后存储在文件中。为了恢复整个 map ，新命令仍然需要处理两点的坐标。一个位于 map 的底角 (0,0,0)，然后另一个位于 map 顶部对面的角落，这将始终根据您想要的服务器而有所不同。我解决这个问题的理由是简单地检索每个坐标的二进制数组的长度。不幸的是，我在尝试这样做时运气不佳，而且我真的不知道如何找到二进制数组的维数。显示了数组的打包和解包以及我无法解决的代码部分。
一件奇怪的事情是，如果我像 if 语句那样用那个服务器 ip 地址手动输入数字，bot 会完美运行。只是任何试图编写适用于任何 map 而不仅仅是一张 map 的代码的努力都是徒劳的。
enter code here
def onBackup(self,user,filename):
fn = bakFolder+filename+".backup"
try:
f = open(fn,"r")
self.bot.sendMessage("A backup by that name already exists.")
f.close()
return
except IOError:
try:
f = open(fn,"wb")
f.write(struct.pack("!3i",self.bot.level_x,self.bot.level_y,self.bot.level_z))
self.bot.block_array.tofile(f)
self.bot.sendMessage("Backup saved to file %s.backup"%filename)
print "Backup save to %s.backup"%filename
return
except IOError:
self.bot.sendMessage("Error opening %s.backup"%filename, false)
print "Backup: Error opening file"
return
def restoremap(self):
fn = bakFolder+self.restore_filename+".backup"
try:
f = open(fn,"rb")
header_x, header_y, header_z = struct.unpack('!3i',f.read(12))
backup_array = array.array('B')
backup_array.fromfile(f,header_x*header_y*header_z)
x1,y1,z1 = (0,0,0)
if server == "204.232.197.228":
x2,y2,z2 = (64,1020,64) #special server that already has coordinates
else:
x2,y2,z2 = ??? rest of servers, coordinates derived from the binary array
if x1 > x2 : x1, x2 = x2, x1
if y1 > y2 : y1, y2 = y2, y1
if z1 > z2 : z1, z2 = z2, z1
tiles_to_deglass = []
tiles_to_build = []
while x1 <= x2:
y = y1
while y <= y2:
z = z1
while z <= z2:
offset = self.bot.calculateOffset(x1,y,z)
current_tile = int(self.bot.block_array[offset])
backup_tile = int(backup_array[offset])
if not ( current_tile == backup_tile):
if (current_tile == 0) and (backup_tile in self.valid_blocks):
tiles_to_build.append((backup_tile,x1,y,z))
elif (current_tile >= 8) and (current_tile <= 11) and (backup_tile == 0):
## This deals with water & lava in what used to be empty spaces
## first we'll glass it all, and then deglass later!
self.blocks.append((20,x1,y,z))
tiles_to_deglass.append((0,x1,y,z))
elif backup_tile == 7:##use stone
tiles_to_build.append((0,x1,y,z))
tiles_to_build.append((1,x1,y,z))
elif backup_tile in self.valid_blocks:
## This is the fall through... We'll try to erase
## the current tile and then restore it to the other state
tiles_to_build.append((0,x1,y,z))
tiles_to_build.append((backup_tile,x1,y,z))
elif (backup_tile == 0) and not (current_tile == 0):
tiles_to_build.append((0,x1,y,z))
z+=1
y += 1
x1 +=1
self.DrawBlocks()
self.blocks += tiles_to_build
self.DrawBlocks()
self.blocks += tiles_to_deglass
self.DrawBlocks()
self.bot.sendMessage("Restoring...",ignorable=True)
##self.bot.action_queue.append(SayAction(self.bot,"Done restoring."))
self.onReset(silent=True)
except IOError:
self.bot.sendMessage("Error while restoring (couldn't read file).")
请您参考如下方法:
似乎您唯一使用 x2,y2,z2 的地方是在这些循环中对 x1,y 和 z 设置限制:
while x1 <= x2:
y = y1
while y <= y2:
z = z1
while z <= z2:
offset = self.bot.calculateOffset(x1,y,z)
current_tile = int(self.bot.block_array[offset])
...
z+=1
y += 1
x1 +=1
如果您将 x2 设置得太大会怎样？你有异常(exception)吗？如果是这样， 也许您可以简单地捕获异常以找出 x2 的大小。 例如:
x2=y2=z2=None
while x2 is None or x1<=x2:
y = y1
while y2 is None or y<=y2:
z = z1
while z2 is None or z<=z2:
try:
offset = self.bot.calculateOffset(x1,y,z)
current_tile = int(self.bot.block_array[offset])
except Exception: #<-- Change to most specific exception possible
if z2 is None:
z2=z-1
elif y2 is None:
y2=y-1
elif x2 is None:
x2=x1-1
break
...
z+=1
y += 1
x1 +=1
俗话说，it's easier to ask for forgiveness than permission .
附言。要找出要捕获的特定异常，请删除上面的 try 和 except 并运行脚本，让它失败。回溯错误消息的最后一行告诉您引发的异常类型。例如，它可能会说类似的话
IndexError: x,y,z out of bounds
在这种情况下，添加 try 和 except 将 Exception 更改为 IndexError。
