我是一名 Python 初学者，试图从电子邮件 header 中提取数据。我在一个文本文件中有数千封电子邮件，我想从每封邮件中提取发件人地址、收件人地址和日期，并将其写入新文件中以分号分隔的单个行。
这很丑陋，但这是我想出的:
import re
emails = open("demo_text.txt","r") #opens the file to analyze
results = open("results.txt","w") #creates new file for search results
resultsList = []
for line in emails:
if "From - " in line: #recgonizes the beginning of a email message and adds a linebreak
newMessage = re.findall(r'\w\w\w\s\w\w\w.*', line)
if newMessage:
resultsList.append("\n")
if "From: " in line:
address = re.findall(r'[\w.-]+@[\w.-]+', line)
if address:
resultsList.append(address)
resultsList.append(";")
if "To: " in line:
if "Delivered-To:" not in line: #avoids confusion with 'Delivered-To:' tag
address = re.findall(r'[\w.-]+@[\w.-]+', line)
if address:
for person in address:
resultsList.append(person)
resultsList.append(";")
if "Date: " in line:
date = re.findall(r'\w\w\w\,.*', line)
resultsList.append(date)
resultsList.append(";")
for result in resultsList:
results.writelines(result)
emails.close()
results.close()
这是我的“demo_text.txt”:
From - Sun Jan 06 19:08:49 2013
X-Mozilla-Status: 0001
X-Mozilla-Status2: 00000000
Delivered-To: somebody_1@hotmail.com
Received: by 10.48.48.3 with SMTP id v3cs417003nfv;
Mon, 15 Jan 2007 10:14:19 -0800 (PST)
Received: by 10.65.211.13 with SMTP id n13mr5741660qbq.1168884841872;
Mon, 15 Jan 2007 10:14:01 -0800 (PST)
Return-Path: <nobody@hotmail.com>
Received: from bay0-omc3-s21.bay0.hotmail.com (bay0-omc3-s21.bay0.hotmail.com [65.54.246.221])
by mx.google.com with ESMTP id e13si6347910qbe.2007.01.15.10.13.58;
Mon, 15 Jan 2007 10:14:01 -0800 (PST)
Received-SPF: pass (google.com: domain of nobody@hotmail.com designates 65.54.246.221 as permitted sender)
Received: from hotmail.com ([65.54.250.22]) by bay0-omc3-s21.bay0.hotmail.com with Microsoft SMTPSVC(6.0.3790.2668);
Mon, 15 Jan 2007 10:13:48 -0800
Received: from mail pickup service by hotmail.com with Microsoft SMTPSVC;
Mon, 15 Jan 2007 10:13:47 -0800
Message-ID: <BAY115-F12E4E575FF2272CF577605A1B50@phx.gbl>
Received: from 65.54.250.200 by by115fd.bay115.hotmail.msn.com with HTTP;
Mon, 15 Jan 2007 18:13:43 GMT
X-Originating-IP: [200.122.47.165]
X-Originating-Email: [nobody@hotmail.com]
X-Sender: nobody@hotmail.com
From: =?iso-8859-1?B?UGF1bGEgTWFy7WEgTGlkaWEgRmxvcmVuemE=?=
<nobody@hotmail.com>
To: somebody_1@hotmail.com, somebody_2@gmail.com, 3_nobodies@yahoo.com.ar
Bcc:
Subject: fotos
Date: Mon, 15 Jan 2007 18:13:43 +0000
Mime-Version: 1.0
Content-Type: multipart/mixed; boundary="----=_NextPart_000_d98_1c4f_3aa9"
X-OriginalArrivalTime: 15 Jan 2007 18:13:47.0572 (UTC) FILETIME=[E68D4740:01C738D0]
Return-Path: nobody@hotmail.com
输出是:
somebody_1@hotmail.com;somebody_2@gmail.com;3_nobodies@yahoo.com.ar;Mon, 15 Jan 2007 18:13:43 +0000;
除了我的 demo_text.txt(第 24 行)的“发件人:”字段中有一个换行符外，此输出会很好，所以我错过了“nobody@hotmail.com”。
我不确定如何让我的代码跳过换行符并仍然在 From: 标记中找到电子邮件地址。
更一般地说，我确信有很多更明智的方法来完成这项任务。如果有人能指出我正确的方向，我将不胜感激。
请您参考如下方法:
您的演示文本实际上是 mbox 格式，可以使用 mailbox 模块中的适当对象进行完美处理:
from mailbox import mbox
import re
PAT_EMAIL = re.compile(r"[0-9A-Za-z._-]+\@[0-9A-Za-z._-]+")
mymbox = mbox("demo.txt")
for email in mymbox.values():
from_address = PAT_EMAIL.findall(email["from"])
to_address = PAT_EMAIL.findall(email["to"])
date = [ email["date"], ]
print ";".join(from_address + to_address + date)
