我是一名新程序员，正在为我的计算机科学总结设计一个内存游戏。游戏是这样的:计算机在随机位置显示随机框，然后用户必须猜测框的位置并单击它。
我基本上已经完成了，只是现在我正在尝试创建 5 个不同难度的关卡。例如，第 1 级将显示 2 个框，第 2 级将显示 5 个，等等。然后如果用户通过所有级别，他们可以再次玩。我知道很多，但我真的很想在这方面获得 A。
但现在我卡住了，因为在我尝试关闭窗口之前它并没有真正起作用，即使那样它也只进行了一半。任何帮助将不胜感激。
import pygame , sys
import random
import time
size=[500,500]
pygame.init()
screen=pygame.display.set_mode(size)
# Colours
LIME = (0,255,0)
RED = (255, 0, 0)
BLACK = (0,0,0)
PINK = (255,102,178)
SALMON = (255,192,203)
WHITE = (255,255,255)
LIGHT_PINK = (255, 181, 197)
SKY_BLUE = (176, 226, 255)
screen.fill(BLACK)
# Width and Height of game box
width=50
height=50
# Margin between each cell
margin = 5
rows = 20
columns = 20
# Set title of screen
pygame.display.set_caption("Spatial Recall")
# Used to manage how fast the screen updates
clock=pygame.time.Clock()
coord=[]
# Create a 2 dimensional array. A two dimesional
# array is simply a list of lists.
def resetGrid():
grid = []
for row in range(rows):
# Add an empty array that will hold each cell
# in this row
grid.append([])
for column in range(columns):
grid[row].append(0) # Append a cell
return grid
def displayAllPink(pygame):
for row in range(rows):
for column in range(columns):
color = LIGHT_PINK
pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
pygame.display.flip()
def displayOtherColor(pygame,grid):
coord = []
for i in range(random.randint(2,5)):
x = random.randint(2, rows-1)
y = random.randint(2, columns-1)
color = LIME
pygame.draw.rect(screen,color,[(margin+width)*y + margin,(margin+height)*x+margin,width,height])
coord.append((x,y))
grid[x][y] = 1
pygame.display.flip()
time.sleep(1)
return coord
def runGame(gameCount,coord,pygame,grid):
pygame.event.clear()
pygame.display.set_caption("Spatial Recall: Level "+ str(gameCount))
pygame.time.set_timer(pygame.USEREVENT,1000)
time = 0
#clock.tick(
# -------- Main Program Loop -----------
#Loop until the user clicks the close button.
done = False
while done==False:
event = pygame.event.wait() # User did something
if event.type == pygame.QUIT: # If user clicked close
done=True # Flag that we are done so we exit this loop
pygame.event.clear()
print "Game ",gameCount, "ends"
elif event.type == pygame.USEREVENT:
time = time + 1
pygame.display.set_caption("Spatial Recall: Level "+ str(gameCount) + " Time: "+ str(time))
if time == 100:
done = True
pygame.display.set_caption("Time out, moving to next level")
pygame.event.clear()
return False
elif event.type == pygame.MOUSEBUTTONDOWN:
# User clicks the mouse. Get the position
pos = pygame.mouse.get_pos()
# Change the x/y screen coordinates to grid coordinates
column=pos[0] // (width+margin)
row=pos[1] // (height+margin)
if (row,column) in coord:
print coord
coord.remove((row,column))
print coord
color = LIME
pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
if coord == []:
done=True
pygame.display.set_caption("Time out, moving to next level")
pygame.event.clear()
return True
else:
color = RED
pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
pygame.display.flip()
def startTheGame(gameCount):
grid = resetGrid()
displayAllPink(pygame)
coord = displayOtherColor(pygame,grid)
displayAllPink(pygame)
runGame(gameCount,coord,pygame,grid)
for i in range(2):
startTheGame(i+1)
pygame.quit ()
请您参考如下方法:
您可能需要使用 pygame.font 模块。 http://pygame.org/docs/ref/font.html
- 首先，从文件或系统字体函数之一加载字体。
- 调用
YourFontObject.render(your_text_string)。这将返回一个Surface，其中包含以给定字体呈现的字符串。请注意，您不能使用换行符 (\n)!您必须自己设置间距。 - 在其他所有内容之后将此
Surface复制到屏幕上，这样就不会遮挡它。
此外，您的函数中不需要 pygame 参数。
希望这对您有所帮助。
