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python之网页抓取 HTML 标签,包括所有链接内的标签

2025年05月04日12zdz8207

我将 BeautifulSoup 与 Python 3.5 一起使用,我正在尝试为所有 h 标签(因此所有 h1、h2.. 等)抓取一个网站。我的问题是让程序打开网站上的其他链接来抓取他们的标签。

假设我有一个带有导航菜单的网站,其中一些链接遍及整个网站,并且所有链接都包含某种 h-tags。我将如何在我选择的网站上抓取所有这些内容?

这是我目前用来抓取特定 url 中的 h1 标签的代码:

import requests 
from bs4 import BeautifulSoup 
 
url = "http://dsv.su.se/en/research" 
 
r = requests.get(url) 
 
soup = BeautifulSoup(r.content, "html.parser") 
 
h1_data = soup.find_all("h1") 
 
for item in h1_data: 
    print (item.contents[0]) 

我希望我说得够清楚了。谢谢。

请您参考如下方法:

使用您的示例 url,我们可以从 HeadRowMenu 获取所有 url,并使用循环从每个页面中提取所有 h1。

import requests 
from bs4 import BeautifulSoup 
from urllib.parse import urljoin 
 
url = "http://dsv.su.se/en" 
 
base = "http://dsv.su.se" 
 
 
def crawl(start, base): 
    r = requests.get(start) 
    soup = BeautifulSoup(r.content, "lxml") 
    hs = ["h1", "h2", "h3", "h4", "h5", "h6"] 
    menu_links = [urljoin(base, a["href"]) for a in soup.select("#HeadRowMenu a")][1:] 
    for h in hs: 
        yield soup.find_all(h) 
    for lnk in menu_links: 
        soup = BeautifulSoup(requests.get(lnk).content) 
        for h in hs: 
            yield soup.find_all(h) 

如果我们运行它:

In [17]: print(list(chain.from_iterable(crawl(url, base)))) 
 
[<h1 class="visuallyhidden">Department of Computer and Systems Sciences</h1>, <h1> 
<a href="/en/about/news/improve-your-digital-competences-on-line-with-eskills-match-1.278510">Improve your digital competences on-line with eSkills Match</a> 
</h1>, <h1> 
<a href="/en/about/news/envisioning-equality-in-computer-science-tomorrow-today-1.272045">Envisioning Equality in Computer Science - Tomorrow Today</a> 
</h1>, <h1> 
<a href="/en/about/news/egovlab-develops-online-democracy-1.271839">eGovlab develops online democracy</a> 
</h1>, <h1> 
<a href="/en/about/events/vinnova-and-dsv-invite-you-to-a-seminar-about-horizon-2020-1.266104">Vinnova and DSV invite you to a seminar about Horizon 2020</a> 
</h1>, <h1> 
<a href="/en/about/news/significant-increase-of-applicants-for-international-programmes-1.265744">Significant increase of applicants for international programmes</a> 
</h1>, <h1>News</h1>, <h2>Semester start information</h2>, <h2>Meet our students</h2>, <h1 class="visuallyhidden">Education</h1>, <h1>Welcome to the education web at DSV!</h1>, <h1>Master's Programmes at DSV</h1>, <h2> 
    Master's Programmes in English:</h2>, <h1 class="visuallyhidden">Research</h1>, <h1>Research highlights</h1>, <h2>Research news</h2>, <h1 class="visuallyhidden">About us</h1>, <h1>About DSV</h1>, <h2>Sweden's oldest IT department</h2>, <h2>Interdisciplinary education and research</h2>, <h2>Right in the middle of one of the world's leading ICT clusters</h2>, <h1 class="visuallyhidden">Internal</h1>, <h1>Internal</h1>, <h2>Semester start information</h2>, <h2>Meet our students</h2>] 

如果你想从字面上抓取网站上的每个链接,你应该查看 scrapy ,这不是一件容易的事,因为你不能盲目地访问你找到的每一个链接,因为这实际上可以把你带到任何地方并无限循环。你需要确保你只访问你想要的域,你可以用 scrapy 很容易地做到这一点。看看 crawlspider .

自己滚动:

import requests 
from bs4 import BeautifulSoup 
from urllib.parse import urljoin 
 
 
class Crawl: 
    def __init__(self, start_url, allowed, base, select): 
        self.start_url = start_url 
        self.base = base 
        self.allowed_domain = allowed 
        self.crawled = set() 
        self.select = select 
 
    def start(self): 
        r = requests.get(self.start_url) 
        soup = BeautifulSoup(r.content, "lxml") 
        menu_links = [urljoin(self.base, a["href"]) for a in soup.select(self.select)] 
        for lnk in menu_links: 
            yield from self.crawl(lnk) 
 
    def crawl(self, lnk): 
        r = requests.get(lnk) 
        soup = BeautifulSoup(r.content, "lxml") 
        hs = ["h1", "h2", "h3", "h4", "h5", "h6"] 
        page_links = (a["href"] for a in soup.select("a[href]")) 
        joined = (urljoin(base, lnk) if lnk.startswith("/en/") else lnk for lnk in page_links) 
        for lnk in filter(lambda link: link.startswith("http"), joined): 
            if lnk not in self.crawled: 
                soup = BeautifulSoup(requests.get(lnk).content,"lxml") 
                for h in hs: 
                    yield soup.find_all(h) 
            self.crawled.add(lnk) 

示例运行:

In [2]: from itertools import chain     
In [3]: url = "http://dsv.su.se/en"     
In [4]: base = "http://dsv.su.se"     
In [5]: crawler = Crawl(url, "dsv.su.se", base, "#HeadRowMenu a")  
 
In [6]: for h in chain.from_iterable(crawler.start()): 
   ...:          print(h) 
   ...:      
<h1 class="visuallyhidden">Institutionen för data- och systemvetenskap</h1> 
<h1> 
<a href="/omdsv/evenemang/dsv-50-%C3%A5r-digitala-aff%C3%A4rer-%C3%B6ppet-jubileumsseminarium-1.274298">*DSV 50 år* - Digitala affärer - öppet jubileumsseminarium </a> 
</h1> 
<h1> 
<a href="/omdsv/nyheter/premi%C3%A4r-f%C3%B6r-vandringsdramat-exil-fria-poeter-p%C3%A5-flykt-1.278502">Premiär för vandringsdramat Exil - fria poeter på flykt</a> 
</h1> 
<h1> 
<a href="/omdsv/nyheter/nu-b%C3%B6r-det-st%C3%A5-klart-att-n%C3%A5got-m%C3%A5ste-g%C3%B6ras-1.277680">Nu bör det stå klart att något måste göras </a> 
</h1> 
<h1> 
<a href="/omdsv/nyheter/hur-enkelt-%C3%A4r-det-f%C3%B6r-fbi-att-kn%C3%A4cka-en-iphone-utan-apples-hj%C3%A4lp-1.277546">Hur enkelt är det för FBI att knäcka en Iphone utan Apples hjälp?</a> 
</h1> 
<h1> 
<a href="/omdsv/nyheter/1-av-2-vill-l%C3%A5ta-staten-hacka-sig-in-i-datorer-1.277367">Svårt att backa tillbaka från ökad övervakning</a> 
</h1> 
<h1>Senaste nyheterna</h1> 
<h2 class="category">Kommande evenemang</h2> 
<h2>Information inför terminsstart</h2> 
<h1 class="visuallyhidden">Other languages</h1> 
<h1>Other languages</h1> 
<h2> 
    Information in Chinese and Russian</h2> 
<h2>Contact The Administration of Studies</h2> 
<h1 class="visuallyhidden">Department of Computer and Systems Sciences</h1> 
<h1> 
<a href="/en/about/news/improve-your-digital-competences-on-line-with-eskills-match-1.278510">Improve your digital competences on-line with eSkills Match</a> 
</h1> 
<h1> 
<a href="/en/about/news/envisioning-equality-in-computer-science-tomorrow-today-1.272045">Envisioning Equality in Computer Science - Tomorrow Today</a> 
</h1> 
<h1> 
<a href="/en/about/news/egovlab-develops-online-democracy-1.271839">eGovlab develops online democracy</a> 
</h1> 
<h1> 
<a href="/en/about/events/vinnova-and-dsv-invite-you-to-a-seminar-about-horizon-2020-1.266104">Vinnova and DSV invite you to a seminar about Horizon 2020</a> 
</h1> 
<h1> 
<a href="/en/about/news/significant-increase-of-applicants-for-international-programmes-1.265744">Significant increase of applicants for international programmes</a> 
</h1> 
<h1>News</h1> 
<h2>Semester start information</h2> 
<h2>Meet our students</h2> 
................................... 

显然,如果您想更深入,您将需要添加更多逻辑,将所有链接存储在一个结构中并循环直到它为空。像这样的东西:

import requests 
from bs4 import BeautifulSoup 
from urllib.parse import urljoin 
from time import sleep 
 
class Crawl: 
    def __init__(self, start_url, allowed, base, select): 
        self.start_url = start_url 
        self.base = base 
        self.allowed_domain = allowed 
        self.crawled = set() 
        self.select = select 
        self.urls = set() 
 
    def start(self): 
        r = requests.get(self.start_url) 
        soup = BeautifulSoup(r.content, "lxml") 
        menu_links = [urljoin(self.base, a["href"]) for a in soup.select(self.select)] 
        print(menu_links) 
        for lnk in menu_links: 
            yield from self.crawl(lnk) 
 
    def filter_urls(self, soup): 
        page_links = [a["href"] for a in soup.select("a[href]")] 
        joined = (urljoin(base, lnk) if lnk.startswith("/en/") else lnk for lnk in page_links) 
        return set(filter(lambda lnk: self.allowed_domain in lnk, joined)) 
 
 
    def crawl(self, lnk): 
        r = requests.get(lnk) 
        soup = BeautifulSoup(r.content, "lxml") 
        hs = ["h1", "h2", "h3", "h4", "h5", "h6"] 
        self.urls.update(self.filter_urls(soup)) 
        while self.urls: 
            nxt = self.urls.pop() 
            if nxt not in self.crawled: 
                try: 
                    soup = BeautifulSoup(requests.get(nxt).content, "lxml") 
                except requests.exceptions.RequestException as e: 
                    print(e.strerror) 
                    self.crawled.add(nxt) 
                    continue 
                self.urls.update((self.filter_urls(soup) - self.crawled)) 
                for h in hs: 
                    yield soup.find_all(h) 
            self.crawled.add(nxt) 
            sleep(.1) 

这将访问网址中包含 dsv.su.se 的网站上的每个链接,但请注意,有很多链接需要抓取,因此请准备好等待一段时间。