python之可被 3 整除的正则表达式过滤器编号

我有一个逗号分隔的 ids(digits) 列表。我只需要得到能被 3 整除的那些。

示例: i = "3454353, 4354353, 345352, 2343242, 2343242 ..."

请您参考如下方法:

只是为了它:

reobj = re.compile( 
    r"""\b            # Start of number 
    (?:               # Either match... 
     [0369]+          # a string of digits 0369 
    |                 # or 
     [147]            # 1, 4 or 7 
     (?:              # followed by 
      [0369]*[147]    # optional 0369s and one 1, 4 or 7 
      [0369]*[258]    # optional 0369s and one 2, 4 or 8 
     )*               # zero or more times, 
     (?:              # followed by 
      [0369]*[258]    # optional 0369s and exactly one 2, 5 or 8 
     |                # or 
      [0369]*[147]    # two more 1s, 4s or 7s, with optional 0369s in-between. 
      [0369]*[147] 
     ) 
    |                 # or the same thing, just the other way around, 
     [258]            # this time starting with a 2, 5 or 8 
     (?: 
      [0369]*[258] 
      [0369]*[147] 
     )* 
     (?: 
      [0369]*[147] 
     | 
      [0369]*[258] 
      [0369]*[258] 
     ) 
    )+                # Repeat this as needed 
    \b                # until the end of the number.""",  
    re.VERBOSE) 
result = reobj.findall(subject) 

将查找字符串中所有可被 3 整除的数字。