Python 作业——创建一个新列表

作业:

Write a function called splitList(myList, option) that takes, as input, a list and an option, which is either 0 or 1. If the value of the option is 0, the function returns a list consisting of the elements in myList that are negative, and if the value of the option is 1, the function returns a list consisting of the elements in myList that are even.

我知道如何判断一个数是偶数还是负数。我正在努力研究如何根据“选项”返回一个新的负数或偶数列表

这是我到目前为止得到的:

def splitList(myList): 
    newlist = [] 
    for i in range(len(myList)): 
        if (myList[i]%2 == 0): 
           newlist.append(myList [i]) 
    return newlist 

这个程序报错如下:

Traceback (most recent call last): File "<string>", line 1, in <fragment>  
builtins.TypeError: splitList() takes exactly 1 positional argument (4 given) 

请您参考如下方法:

正如我在评论中提到的，您应该标准化缩进:四个空格是 Python 标准。您通常可以将编辑器设置为插入四个空格而不是制表符(也不想将制表符与空格混合)。

关于您的实际问题:尝试编写总共三个函数:一个返回所有负值，一个返回偶数，一个根据 option 调用适当的函数。

def splitlist(myList, option): 
    if option == 1: 
        return get_even_elements(myList) 
    elif option == 0: 
        return get_negative_elements(myList) 
 
def get_even_elements(myList): 
    pass # Implementation this method here. 
 
def get_negative_elements(myList): 
    pass # Implementation this method here. 
 
# Test it out! 
alist = [-1, 2, -8, 5] 
print splitlist(alist, 0) 
print splitlist(alist, 1)