我正在做这本书中的教程，在 24 小时内自学 Django，在第 1 部分的第 4 小时，我陷入了这个错误。

Traceback (most recent call last): 
 
  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 278, in run 
    self.result = application(self.environ, self.start_response) 
 
  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 635, in __call__ 
    return self.application(environ, start_response) 
 
  File "C:\Python25\lib\site-packages\django\core\handlers\wsgi.py", line 239, in __call__ 
    response = self.get_response(request) 
 
  File "C:\Python25\lib\site-packages\django\core\handlers\base.py", line 67, in get_response 
    response = middleware_method(request) 
 
  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 56, in process_request 
    if (not _is_valid_path(request.path_info) and 
 
  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 142, in _is_valid_path 
    urlresolvers.resolve(path) 
 
  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 254, in resolve 
    return get_resolver(urlconf).resolve(path) 
 
  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 181, in resolve 
    for pattern in self.url_patterns: 
 
  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 205, in _get_url_patterns 
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module) 
 
  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 200, in _get_urlconf_module 
    self._urlconf_module = __import__(self.urlconf_name, {}, {}, ['']) 
 
  File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module> 
    (r'^admin/', include('django.contribute.admin.urls')) 
 
TypeError: 'tuple' object is not callable

谁能帮帮我..

网址.py

from django.conf.urls.defaults import * 
 
####Uncomment the next two lines to enable the admin: 
#### from django.contrib import admin 
#### admin.autodiscover() 
 
urlpatterns = patterns('', 
    (r'^People/$', 'iFriends.People.views.index') , 
    (r'^admin/', include('django.contrib.admin.urls')),  
    # Example: 
    # (r'^iFriends/', include('iFriends.foo.urls')), 
 
    # Uncomment the admin/doc line below and add 'django.contrib.admindocs'  
    # to INSTALLED_APPS to enable admin documentation: 
    # (r'^admin/doc/', include('django.contrib.admindocs.urls')), 
 
    # Uncomment the next line to enable the admin: 
 
 
)

请您参考如下方法:

您以某种方式将一些函数设置为一个元组。请编辑问题并粘贴您的 urls.py 代码，以便我们指出错误。

我可以尝试大胆猜测:

File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module> 
   (r'^admin/', include('django.contribute.admin.urls'))

这不知何故告诉我你在第 16 行漏掉了一个逗号，所以:

16. (r'^/', 'some_stuff....')      # <-- missed comma here 
17. (r'^admin/', include('django.contribute.admin.urls'))

只需输入逗号即可。如果不是这样，我会把我的 Crystal 球送去维修。粘贴代码。

编辑

您似乎粘贴了 urls.py 作为答案。请编辑问题并将 urls.py 粘贴到那里。

不管怎样，错误已经改变了。你做了什么？在这个新错误中，urls.py 不再找到，所以也许您已经重命名了它？您是否更改了运行应用程序的方式？

您粘贴的文件不是正在运行的文件。你在粘贴 url.py 而 django 正在读取 urls.py 吗？错误中的代码与您粘贴的代码不匹配!请粘贴正确的文件，即给出错误的文件，否则我们无能为力。

python之类型错误 : 'tuple' object is not callable

编辑