python之将元组列表转换为字典列表

我有一个元组列表:

[('Lebron James', datetime.date(2017, 12, 23), 500), 
 ('Julie Peralta', datetime.date(2017, 12, 13), 1500), 
 ('Reynaldo Pahay', datetime.date(2017, 12, 11), 2500)] 

我想把它转换成一个字典列表:

[{'Name': 'Lebron James', 'date': datetime.date(2017, 12, 23), 'penalty': 500}, 
 {'Name': 'Julie Peralta', 'date': datetime.date(2017, 12, 13), 'penalty': 1500}, 
 {'Name': 'Reynaldo Pahay', 'date': datetime.date(2017, 12, 11), 'penalty': 2500}] 

最好和最有效的方法是什么？

请您参考如下方法:

您可以使用 zip功能。

import datetime 
 
def get_list_of_dict(keys, list_of_tuples): 
     """ 
     This function will accept keys and list_of_tuples as args and return list of dicts 
     """ 
     list_of_dict = [dict(zip(keys, values)) for values in list_of_tuples] 
     return list_of_dict 

演示

keys = ("name", "date", "penalty") 
my_list_of_tuples = [ 
                      ('Lebron James', datetime.date(2017, 12, 23), 500),  
                      ('Julie Peralta', datetime.date(2017, 12, 13), 1500),  
                      ('Reynaldo Pahay', datetime.date(2017, 12, 11), 2500) 
                    ] 
 
 
print(get_list_of_dict(keys, my_list_of_tuples)) 
#output 
#[{'date': datetime.date(2017, 12, 23), 'penalty': 500, 'name': 'Lebron James'}, {'date': datetime.date(2017, 12, 13), 'penalty': 1500, 'name': 'Julie Peralta'}, {'date': datetime.date(2017, 12, 11), 'penalty': 2500, 'name': 'Reynaldo Pahay'}]