函数在参数列表中接收末尾有很多 0 的参数，例如:
[48, 39, 23, 15, 11, 12, 5, 9, 7, 3, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0]
[137, 30, 12, 3, 1, 0, 0, 0]
如果列表的长度和末尾零的数量总是不同，我如何从零开始修剪它以得到
[48, 39, 23, 15, 11, 12, 5, 9, 7, 3, 4, 2, 0, 0, 1, 0 , 1]
[137, 30, 12, 3, 1]
请您参考如下方法:
list1 = [48, 39, 23, 15, 11, 12, 5, 9, 7, 3, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0]
list2 = [137, 30, 12, 3, 1, 0, 0, 0]
def pop_zeros(items):
while items[-1] == 0:
items.pop()
pop_zeros(list1)
pop_zeros(list2)
print(list1)
print(list2)
输出
[48, 39, 23, 15, 11, 12, 5, 9, 7, 3, 0, 0, 1, 0, 1]
[137, 30, 12, 3, 1]
