是否可以简化这个?也许结合两者?教我 DRY 的方法 :-\
o = old_last_result
if o == 7:
old_last_result_msg = result_7
elif o == 12:
old_last_result_msg = result_12
elif o == 23:
old_last_result_msg = result_23
elif o == 24:
old_last_result_msg = result_24
elif o == 103:
old_last_result_msg = result_103
elif o == 1000:
old_last_result_msg = result_1000
else:
old_last_result_msg = "Error code: #%s" % old_last_result
n = new_last_result
if n == 7:
new_last_result_msg = result_7
elif n == 12:
new_last_result_msg = result_12
elif n == 23:
new_last_result_msg = result_23
elif n == 24:
new_last_result_msg = result_24
elif n == 103:
new_last_result_msg = result_103
elif n == 1000:
new_last_result_msg = result_1000
else:
new_last_result_msg = "Error code: #%s" % new_last_result
请您参考如下方法:
result_msgs = {
7: result_7,
12: result_12,
...
}
old_last_result_msg = result_msgs.get(old_last_result,
"Error code: #%s" % old_last_result)
new_last_result_msg = result_msgs.get(new_last_result,
"Error code: #%s" % new_last_result)
