我目前正在尝试用 Python 编写我的第一个程序/应用程序，方法是创建一个工具供我的合作伙伴在我们玩纸牌游戏时使用。我刚刚开始认真学习编程，所以这可能是我错过的一个菜鸟错误，但我似乎无法通过输入捕捉到“其他任何东西”来转移用户的 react 。
这是我的代码:
def counting_up ():
round_total = 0
while True :
global game_level
cards = input("Enter Card: \n")
if cards.upper() == "A" or cards == "2" :
round_total += 20
if cards == "3" :
round_total += 3
if cards == "4":
round_total += 4
if cards == "5" :
round_total += 5
if cards == "6" :
round_total += 6
if cards == "7" :
round_total += 7
if cards == "8" :
round_total += 8
if cards == "9" :
round_total += 9
if cards == "10" or cards.upper() == "J" or cards.upper() == "Q" or cards.upper() == "K" :
round_total += 10
if cards == "0" :
game_level += 1
if cards.upper() == "END" :
game_state = 1
break
else :
print (f"{cards}, is not a valid value, please enter a valid value!")
print ("Your score this round was " + str(round_total))
return round_total
在测试时，它似乎在得出其无效值的结论之前没有经过先前的逻辑检查。请注意，这整个功能都按预期工作，如果我在最后删除 else: 语句，它也会正常工作。 python 中是否有类似于 java 中的 case 语句的东西可以工作？
提前致谢
请您参考如下方法:
在同一层有多个if 语句，python 将检查每个条件语句。如果您希望它在满足前一个语句时忽略后续语句，请使用 elif:
def counting_up(game_state, game_level, round_total=0):
"""Request and add input card face value to score repeatedly till end."""
while True:
cards = input("Enter Card: \n")
if cards.upper() == "END":
game_state = 1; break
elif cards == "0":
game_level += 1
elif cards.upper() in ("A", "2"):
round_total += 20
elif cards.isnumeric():
round_total += int(cards)
elif cards.upper() in ("J","Q","K"):
round_total += 10
else:
print(f"{cards}, is not a valid value, please enter a valid value!")
print(f"Your score this round was {round_total}.")
return round_total
