我有一个这样的数组，
a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
我想列出小于 7 的值(如下所示)
b = [[3,2,5],[4,5,6,3],[4,5],[5],[4],[6]]
所以我用了下面的方法，
>>> from itertools import takewhile
>>> a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
>>>list(takewhile(lambda x: x < 7 , a))
[3, 2, 5]
但我只得到第一个序列。谁能帮我解决这个问题？ 谢谢。
请您参考如下方法:
a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
from itertools import groupby
[list(g) for k, g in groupby(a, lambda x:x<7) if k]
输出:
[[3, 2, 5], [4, 5, 6, 3], [4, 5], [5], [4], [6]]
