python之对字典进行排序-声明 python 的顺序

我在这里添加了生成 xml_tags 的代码，这就是我的输出:

md5 value = "sdfhsdkjgfjw35378563" 
repOperation value = "push" 
size value = "toolarge" 
images value = "/home/rakesh/from_t_jack/imag1.ipds" 
status value = "completed" 
replication value = "mode" 
sdlist value = "f:" 

我用过字典。我无法对我的字典进行正确的排序。我希望字典按照我声明的顺序进行排序和打印。 另一个问题是，如果在第 6 行观察到输出，则输出有点相反，我期待:mode value = "replication"。但输出是相反的。我不知道为什么它会以这种方式表现。我想知道如何解决这两个问题。这是我的代码。

  def generate_tag(name,val): 
 
     full_tag = ''+name+' value = "'+val+'"' 
     return full_tag 
 
 
 
  def auto_xml(sdList,repOperation,images,status,md5): 
 
 
            tags =          {'repOperationTag'  :{'repOperation_tag_name':'repOperation' , 
                                                  'repOperation_val'     : repOperation }, 
 
                            'modeTag'             :{'mode_tag_name':'mode' , 
                                                    'mode_val'     : 'replication' }, 
 
 
                             'imagesTag'        :{'images_tag_name': 'images', 
                                                  'images_val'     : images  }, 
 
                             'statusTag'        :{'status_tag_name':'status' , 
                                                  'status_val'     : status}, 
 
                            'sizeTag'          :{'size_tag_name':'size' , 
                                                 'size_val'     : 'toolarge'}, 
 
                             'md5Tag'           :{'md5_tag_name'    : 'md5' , 
                                                  'md5_val'         : md5} , 
 
                             'sdListTag'        :{'sdList_tag_name': 'sdlist' ,  
                                                  'sdList_val'     : sdList} } 
 
            count = 0 
            tag_len = len(tags) 
 
            while count < tag_len : 
 
                inner = tags[tags.keys()[count]] 
 
                tag_name = inner[inner.keys()[0]] 
                tag_val = inner[inner.keys()[1]] 
 
                full_tag = generate_tag(tag_name,tag_val) 
 
                print full_tag 
                count = count + 1 
 
 
 
  def myordered_dict():  
 
      from collections import OrderedDict 
 
 
      tags =         {'A_repOperationTag'  :{'tag_name':'repOperation' , 
                                      'tag_val'     : repOperation }, 
 
                'B_modeTag'             :{'tag_name':'mode' , 
                                        'tag_val'     : 'replication' }, 
 
 
                'C_imagesTag'        :{'tag_name': 'images', 
                                      'tag_val'     : images  }, 
 
                'D_statusTag'        :{'tag_name':'status' , 
                                      'tag_val'     : status}, 
 
                'E_sizeTag'          :{'tag_name':'size' , 
                                     'tag_val'     : 'toolarge'}, 
 
                'F_md5Tag'           :{'tag_name'    : 'md5' , 
                                      'tag_val'         : md5} , 
 
                'G_sdListTag'        :{'tag_name': 'sdlist' ,  
                                      'tag_val'     : sdList}, 
 
                'H_machinename'        :{'tag_name': 'hostname' ,  
                                      'tag_val'     : 'xp_vm'} } 
 
      tags = OrderedDict(sorted(tags.items(), key=lambda t: t[0]))