python之Python 3 中的用户输入和排序列表

我需要帮助来生成这样的输出:

1. Enter a member: samantha  
Names: ['Samantha'] 
2. Enter a member: susan  
Names: ['Samantha', 'Susan'] 
3. Enter a member: billy  
Names: ['Billy', 'Samantha', 'Susan'] 
4. Enter a member: billy 
4. Enter a member: samantha 
4. Enter a member: Jason  
Names: ['Billy', 'Jason', 'Samantha', 'Susan'] 
5. Enter a member:  
 
Members: 
1. Billy 
2. Jason 
3. Samantha 
4. Susan 

我已经努力创建一个程序来执行此操作，但无济于事。我将在代码本身的问题中发表评论。预先感谢您的帮助。

def function(): 
 
    x = [] 
    #a = "1." # I tried to number the questions by adding these but it doesnt work 
    while True: 
        #a += 1 
        name = input("Enter name: ").title() 
        x.append(name) 
 
        print("Names:", x) 
        #if name == name: # this condition is made so that an input that is typed in again doesn't get included in the list 
            #name = input("Enter name: ").title() 
 
            # where should I add an insert() here to have the list alphabetically ordered? 
 
        if not name: # pressing enter prints out the second half of the output, listing the members 
            #print("\nMembers:", x).sort() 
            break 
 
function() 

请您参考如下方法:

你做的几乎所有事情都是正确的，但问题是你在哪里打破了循环。您首先要附加名称，然后检查输入是否只是一个回车。因此，首先检查输入，然后将其附加到列表中。 这是我的代码:

def fun1(): 
    l = [] 
    while True: 
        s = input("Enter a member: ") 
        if not s: 
            break 
        l.append(s.title()) 
        print("Names:", l) 
    l.sort() 
    print("Members:") 
    for i in range(0, len(l)): 
        print(i+1,end = '') 
        print(".", l[i]) 
fun1() 

希望对您有所帮助。