使用这段代码:
from lxml import etree
with open( 'C:\\Python33\\projects\\xslt', 'r' ) as xslt, open( 'C:\\Python33\\projects\\result', 'a+' ) as result, open( 'C:\\Python33\\projects\\xml', 'r' ) as xml:
s_xml = xml.read()
s_xslt = xslt.read()
transform = etree.XSLT(etree.XML(s_xslt))
out = transform(etree.XML(s_xml))
result.write(out)
我收到这个错误:
Traceback (most recent call last):
File "<pyshell#7>", line 1, in <module>
from projects.xslt_transform import trans
File ".\projects\xslt_transform.py", line 17, in <module>
transform = etree.XSLT(etree.XML(s_xslt))
File "xslt.pxi", line 409, in lxml.etree.XSLT.__init__ (src\lxml\lxml.etree.c:150256)
lxml.etree.XSLTParseError: Invalid expression
这对 xml/xslt 文件可与其他工具一起使用。
此外,我还必须去掉两个文件顶部声明中的编码属性,以免得到:
ValueError: Unicode strings with encoding declaration are not supported. Please use bytes input or XML fragments without declaration.
有关系吗?
编辑:
这也不起作用(我得到同样的错误):
with open( 'C:\\Python33\\projects\\xslt', 'r',encoding="utf-8" ) as xslt, open( 'C:\\Python33\\projects\\result', 'a+',encoding="utf-8" ) as result, open( 'C:\\Python33\\projects\\xml', 'r',encoding="utf-8" ) as xml:
s_xml = etree.parse(BytesIO(bytes(xml.read(),'UTF-8')))
s_xslt = etree.parse(BytesIO(bytes(xslt.read(),'UTF-8')))
transform = etree.XSLT(s_xslt)
out = transform(s_xml)
print(out.tostring())
阅读 lxml 源代码:这将返回一个异常:
xslt.xsltParseStylesheetDoc(c_doc)
所以这似乎是一个实际的解析错误。它可以与 namespace 相关吗?
编辑已解决:
s_xml = etree.parse(xml.read())
s_xslt = etree.parse(xslt.read())
谢谢你
请您参考如下方法:
解析 XML 比“打开一个文本文件,将生成的字符串填充到 etree 中”要复杂得多。
XML 文件是 DOM 树的序列化表示。它们不能作为文本处理,即使它们以文本文件的形式出现。它们采用多字节编码,找出特定文件使用的编码绝非易事。
XML 解析器内置了适当的检测机制,因此应该使用它们来打开 XML 文件。基本的 open() + read() 调用不足以正确处理文件内容。
lxml.etree 提供 the parse() function可以接受多种参数类型:
- an open file object (make sure to open it in binary mode)
- a file-like object that has a .read(byte_count) method returning a byte string on each call
- a filename string
- an HTTP or FTP URL string
然后将关联文档正确解析回 DOM 树。
您的代码应该更像这样:
from lxml import etree
f_xsl = 'C:\\Python33\\projects\\xslt'
f_xml = 'C:\\Python33\\projects\\xml'
f_out = 'C:\\Python33\\projects\\result'
transform = etree.XSLT(etree.parse(f_xsl))
result = transform(etree.parse(f_xml))
result.write(f_out)
