我有一个长字符串，其中包含以下格式的键值:
"info":"infotext","day":"today","12":"here","info":"infotext2","info":"infotext3"
我想获取所有“信息”键的值 (=infotexts)。如何做到这一点？
请您参考如下方法:
使用 json，Luke
s = '"info":"infotext","day":"today","12":"here","info":"infotext2","info":"infotext3"'
import json
def pairs_hook(pairs):
return [val for key, val in pairs if key == 'info']
p = json.loads('{' + s + '}', object_pairs_hook=pairs_hook)
print p # [u'infotext', u'infotext2', u'infotext3']
来自 the docs :
object_pairs_hook is an optional function that will be called with the result of any object literal decoded with an ordered list of pairs. The return value of object_pairs_hook will be used instead of the dict.
为了完整起见，下面是一个执行相同操作的正则表达式:
rg = r'''(?x)
"info"
\s* : \s*
"
(
(?:\\.|[^"])*
)
"
'''
re.findall(rg, s) # ['infotext', 'infotext2', 'infotext3']
这也处理 : 周围的空格和字符串内的转义引号，例如
"info" : "some \"interesting\" information"
