下面是我的代码，我正在使用 Python2.7
#list of angle couples
phipsi=[[48.6,53.4],[-124.9,156.7],[-66.2,-30.8],[-58.8,-43.1], \
[-73.9,-40.6],[-53.7,-37.5],[-80.6,-16.0],[-68.5,135.0], \
[-64.9,-23.5],[-66.9,-45.5],[-69.6,-41.0],[-62.7,-37.5], \
[-68.2,-38.3],[-61.2,-49.1],[-59.7,-41.1],[-63.2,-48.5], \
[-65.5,-38.5],[-64.1,-40.7],[-63.6,-40.8],[-66.4,-44.5], \
[-56.0,-52.5],[-55.4,-44.6],[-58.6,-44.0],[-77.5,-39.1], \
[-91.7,-11.9],[48.6,53.4]]
#minimal deviation tolerated for the 1st number
a=-57-30
#maximal deviation tolerated for the 1st number
b=-57+30
#minimal deviation tolerated for the 2nd number
c=-47-30
#maximal deviation tolerated for the 2nd number
d=-47+30
i=0
#Check if the couple fit into the intervals of numbers
while i < len(phipsi):
if phipsi[i][0]>a and phipsi[i][0]<b:
if phipsi[i][1]>c and phipsi[i][1]<d:
print ('the couple ', phipsi[i] ,' has his angles in helix')
else:
print ('the couple ', phipsi[i] ,' does not have his angles in helix')
i=i+1
这是我得到的
('the couple ', [-55.4, -44.6], ' has his angles in helix')
('the couple ', [-58.6, -44.0], ' has his angles in helix')
('the couple ', [-77.5, -39.1], ' has his angles in helix')
('the couple ', [-91.7, -11.9], ' does not have his angles in helix')
('the couple ', [48.6, 53.4], ' does not have his angles in helix')
如何获取
the couple [-77.5, -39.1] has his angles in helix
the couple [-91.7, -11.9] does not have his angles in helix
我查看了帮助部分或其他符号，但无法弄清楚...谢谢您的帮助
请您参考如下方法:
在 Python 2.x 中，print 不是一个函数，而是一个语句，并且它不包含打印对象列表周围的括号。在 Python 3.x 中，print 被更改为函数。您正在使用 Python 3.x 语法。
你有两个选择:
- 改用 Python 2.x 语法，跳过括号:
print a, b, c - 添加
from __future__ import print_function以禁用 print 语句并改用 print 函数。这使得能够在最近的 Python 2.x 中使用 Python 3.x 语法。
此刻你正在打印一个元组，你看到的是那个元组的repr，即你用print( (a,b,c)) 与 Python 3.x 打印功能。
注意:print 会自动添加空格，无需将它们添加到您的字符串中。
