python之使用django上传文件

以下文件上传代码有什么问题，request.FILES['file'] 看起来是空的

模型:

  from django.db import models  
  from django import forms 
 
  class UploadFileForm(forms.Form): 
      title = forms.CharField(max_length=50) 
      file  = forms.FileField(label="Your file") 

观点:

def index(request): 
  if request.method == 'POST': 
   a=request.POST 
   logging.debug(a["title"]) 
   logging.debug(a["file"]) 
   form = UploadFileForm() 
   form = UploadFileForm(request.POST, request.FILES) 
 
  handle_uploaded_file(request.FILES['file']) 
 
  if form.is_valid(): 
     handle_uploaded_file(request.FILES['file']) 
 
     return HttpResponseRedirect('/Files/') 
else: 
  form = UploadFileForm() 
return render_to_response('Files/index.html', {'form': form}) 
 
 
def handle_uploaded_file(f): 
 logging.debug("here1") 
 #destination = open('some/file/name.txt', 'wb+') 
 destination = open('/tmp', 'wb+') 
 for chunk in f.chunks(): 
   destination.write(chunk) 
 destination.close() 

模板:

      <form name="lang" action="/test/" method="post"> 
      <table> 
     <tr><td> 
     <b> {{ form.file.label_tag }}</b>  {{ form.file}} 
     </td></tr> 
     <tr><td> 
     <input type="hidden" value="title" name="title" id="title" /> 
     <input type="submit" value="Save" id="Save"/> 
     </td></tr> 
     </table> 
    </form> 

请您参考如下方法:

您需要在表单上设置enctype 属性:

<form enctype="multipart/form-data" method="post" action="/foo/"> 

Like they say in the docs.