我是正则表达式的新手，这让我很困惑。
在下面的示例中，我想提取 facebook.com/pages/Dr-Morris-Westfried-Dermatologist/176363502456825?id=176363502456825&sk=info。我已经阅读了惰性量词和回顾，但我仍然无法拼凑出正确的正则表达式。我希望 facebook.com\/.*?sk=info 能正常工作，但它捕获了太多信息。你们能帮忙吗？
<i class="mrs fbProfileBylineIcon img sp_2p7iu7 sx_96df30"></i></span><span class="fbProfileBylineLabel"><span itemprop="address" itemscope="itemscope" itemtype="http://schema.org/PostalAddress"><a href="https://www.facebook.com/pages/Dr-Morris-Westfried-Dermatologist/176363502456825?sk=page_map" target="_self">7508 15th Avenue, Brooklyn, New York 11228</a></span></span></span><span class="fbProfileBylineFragment"><span class="fbProfileBylineIconContainer"><i class="mrs fbProfileBylineIcon img sp_2p7iu7 sx_9f18df"></i></span><span class="fbProfileBylineLabel"><span itemprop="telephone">(718) 837-9004</span></span></span></div></div></div><a class="title" href="https://www.facebook.com/pages/Dr-Morris-Westfried-Dermatologist/176363502456825?id=176363502456825&sk=info" aria-label="About Dr. Morris Westfried - Dermatologist">
请您参考如下方法:
尽管我很喜欢正则表达式，但这是一个 html 解析任务:
>>> from bs4 import BeautifulSoup
>>> html = .... # that whole text in the question
>>> soup = BeautifulSoup(html)
>>> pred = lambda tag: tag.attrs['href'].endswith('sk=info')
>>> [tag.attrs['href'] for tag in filter(pred, soup.find_all('a'))]
['https://www.facebook.com/pages/Dr-Morris-Westfried-Dermatologist/176363502456825?id=176363502456825&sk=info']
