Python 破译

我正在尝试用 Python 破译标准的“a = 1, b = 2, c = 3...”密码，但我有点卡住了。我想要解密的消息是“he”——“8 5”，但由于我的 if 语句的顺序，输出是“eh”。有人知道如何解决这个问题吗？

import re 
import sys 
message = " 8 5 "; 
map(int, re.findall(r'\d+', message)) 
if "++" in message: 
    sys.stdout.write(" ") 
if "--" in message: 
    print() 
if " 1 " in message: 
    sys.stdout.write("a") 
if " 2 " in message: 
    sys.stdout.write("b") 
if " 3 " in message: 
    sys.stdout.write("c") 
if " 4 " in message: 
    sys.stdout.write("d") 
if " 5 " in message: 
    sys.stdout.write("e") 
if " 6 " in message: 
    sys.stdout.write("f") 
if " 7 " in message: 
    sys.stdout.write("g") 
if " 8 " in message: 
    sys.stdout.write("h") 
if " 9 " in message: 
    sys.stdout.write("i") 
if " 10 " in message: 
    sys.stdout.write("j") 
if " 11 " in message: 
    sys.stdout.write("k") 
if " 12 " in message: 
    sys.stdout.write("l") 
if " 13 " in message: 
    sys.stdout.write("m") 
if " 14 " in message: 
    sys.stdout.write("n") 
if " 15 " in message: 
    sys.stdout.write("o") 
if " 16 " in message: 
    sys.stdout.write("p") 
if " 17 " in message: 
    sys.stdout.write("q") 
if " 18 " in message: 
    sys.stdout.write("r") 
if " 19 " in message: 
    sys.stdout.write("s") 
if " 20 " in message: 
    sys.stdout.write("t") 
if " 21 " in message: 
    sys.stdout.write("u") 
if " 22 " in message: 
    sys.stdout.write("v") 
if " 23 " in message: 
    sys.stdout.write("w") 
if " 24 " in message: 
    sys.stdout.write("x") 
if " 25 " in message: 
    sys.stdout.write("y") 
if " 26 " in message: 
    sys.stdout.write("z") 

请您参考如下方法:

如果您使用映射而不是一系列 if 语句，这会变得容易得多:

>>> import string 
>>> d = {str(x):y for x,y in enumerate(string.ascii_lowercase,1)} 
>>> d['++'] = ' ' 
>>> d['--'] = '\n' 
>>> message = ' 8 5 ' 
>>> ''.join(d[x] for x in message.split()) 
'he' 

在这里，我使用所有字符串作为字典的键，因为你想支持 '++' 和 '--'。