我怀疑这个问题以前有人问过,但我没能找到,所以这里是:
在 Python 上(使用 2.7)我创建了一个 namedtuple 如下:
>>> sgn_tuple = namedtuple('sgnt',['signal','type'])
>>> a = sgn_tuple("aaa","bbb")
然后我想检查 t 的类型,我的结果很奇怪:
>>> type (a)
<class '__main__.sgnt'>
>>> a is tuple
False
>>> a is namedtuple
False
>>> a is sgnt
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'sgnt' is not defined
>>> a is sgn_tuple
False
>>>
为什么会这样?我希望 a 被识别为元组类型,但事实并非如此。有什么提示吗?
请您参考如下方法:
is 不检查类成员。 is 检查两个对象是否具有相同的 id
>>> isinstance(a, tuple)
True
另外type(a)不是tuple,a是tuple的子类。
如果您输入 verbose=True,您可以看到它是如何制作的(文本是动态生成的以创建类):
>>> sgn_tuple = namedtuple('sgnt',['signal','type'],verbose=True)
class sgnt(tuple):
'sgnt(signal, type)'
__slots__ = ()
_fields = ('signal', 'type')
def __new__(_cls, signal, type):
'Create new instance of sgnt(signal, type)'
return _tuple.__new__(_cls, (signal, type))
@classmethod
def _make(cls, iterable, new=tuple.__new__, len=len):
'Make a new sgnt object from a sequence or iterable'
result = new(cls, iterable)
if len(result) != 2:
raise TypeError('Expected 2 arguments, got %d' % len(result))
return result
def __repr__(self):
'Return a nicely formatted representation string'
return 'sgnt(signal=%r, type=%r)' % self
def _asdict(self):
'Return a new OrderedDict which maps field names to their values'
return OrderedDict(zip(self._fields, self))
__dict__ = property(_asdict)
def _replace(_self, **kwds):
'Return a new sgnt object replacing specified fields with new values'
result = _self._make(map(kwds.pop, ('signal', 'type'), _self))
if kwds:
raise ValueError('Got unexpected field names: %r' % kwds.keys())
return result
def __getnewargs__(self):
'Return self as a plain tuple. Used by copy and pickle.'
return tuple(self)
signal = _property(_itemgetter(0), doc='Alias for field number 0')
type = _property(_itemgetter(1), doc='Alias for field number 1')
这只是由 Python 执行。我希望一切都清楚。
