我正在寻找一种方法来缩短这个 python3 函数。该函数需要大量输入变量并检查每个变量以查看它是否为 None。有没有办法遍历所有输入变量并将不是 None 的变量添加到 params 字典中？
def news(self, query = None, instrument_id = None, days = None, news_lang = None, news_country = None, market_id = None, limit = None, offset = None, source_id = None):
params = {}
if query is not None:
params['query'] = query
if instrument_id is not None:
params['instrument_id'] = instrument_id
if news_lang is not None:
params['news_lang'] = news_lang
if news_country is not None:
params['news_country'] = news_country
if limit is not None:
params['limit'] = limit
if offset is not None:
params['offset'] = offset
if source_id is not None:
params['source_id'] = source_id
self.make_cmd('GET', 'news', params)
请您参考如下方法:
看起来所有参数都被直接传递给 make_cmd 所以为什么不使用关键字参数:
def news(self, **params):
self.make_cmd('GET', 'news', params)
news(query="Test")
