我有一个元组列表:
lst = [(1, "text"), (2, "more"), (5, "more"), (10, "more")]
元组的结构为(int, string)，从 1 开始，最大值为 10。我想将它们编辑并重新排序为:
lst2 = [(1, "text"), (2, "more"), (3, ""), (4, ""), (5, "more"), (6, ""), (7, ""), (8, ""),
(9, ""), (10, "more")]
如您所见，我想创建一个连续编号为 10 的新列表。所有 int 来自第一个列表 lst 中的元组，不在 1 到10 将在新列表 lst2 中生成一个空字符串。
我想出了这段代码:
lst2 = []
for tupl in lst:
for k in range(1,11):
if tupl[0] == k:
lst2.append((k, tupl[1]))
else:
lst2.append((k, ""))
print lst2
但是结果很奇怪:
[(1, 'text'), (2, ''), (3, ''), (4, ''), (5, ''), (6, ''), (7, ''), (8, ''), (9, ''),
(10, ''), (1, ''), (2, 'more'), (3, ''), (4, ''), (5, ''), (6, ''), (7, ''), (8, ''),
(9, ''), (10, ''), (1, ''), (2, ''), (3, ''), (4, ''), (5, 'more'), (6, ''), (7, ''),
(8, ''), (9, ''), (10, ''), (1, ''), (2, ''), (3, ''), (4, ''), (5, ''), (6, ''), (7, ''),
(8, ''), (9, ''), (10, 'more')]
任何人都可以帮助我或告诉我我做错了什么吗？谢谢。
请您参考如下方法:
lst = [(1, "text"), (2, "more"), (5, "more"), (10, "more")]
d = dict(lst)
lst2 = [(i, d.get(i, "")) for i in range(1, 11)]
编辑
或者，使用 defaultdict :
lst = [(1, "text"), (2, "more"), (5, "more"), (10, "more")]
from collections import defaultdict
d = defaultdict(str, lst)
lst2 = [(i, d[i]) for i in range(1, 11)]
