python之Python 中的二进制到 ASCII

我正在尝试解码位于 .txt 文件中的二进制文件，但我卡住了。我看不出有任何可能解决这个问题。

def code(): testestest 
  ascii = {'01000001':'A', ...} 
  binary = {'A':'01000001', ...} 
  print (ascii, binary) 
 
  def encode(): 
    pass 
 
  def decode(code,n): 
    f = open(code, mode='rb') # Open a file with filename <code> 
    while True: 
      chunk = f.read(n)           # Read n characters at time from an open file 
      if chunk == '':             # This is one way to check for the End Of File in Python  
        break 
      if chunk != '\n': 
        # Process it???? 
        pass 

如何获取 .txt 文件中的二进制文件并将其输出为 ASCII？

请您参考如下方法:

从您的示例来看，您的输入看起来像是二进制格式数字的字符串。

如果是这样，你不需要字典:

def byte_to_char(input): 
     return chr(int(input, base=2)) 

使用您在评论中提供的数据，您必须将二进制字符串拆分为字节。

input ='01010100011010000110100101110011001000000110100101110011001000000110101001110101011100110111010000100000011000010010000001110100011001010111001101110100001000000011000100110000001110100011000100110000' 
length = 8 
input_l = [input[i:i+length] for i in range(0,len(input),length)] 

然后，将每个字节转换成一个字符:

input_c = [chr(int(c,base=2)) for c in input_l] 
print ''.join(input_c) 

综合起来:

def string_decode(input, length=8): 
    input_l = [input[i:i+length] for i in range(0,len(input),length)] 
    return ''.join([chr(int(c,base=2)) for c in input_l]) 
 
decode(input) 
>'This is just a test 10:10'