python之按值对元组排序，当值相等时使用列表

我有一个列表:

test1 = ["a","b","c","d","e","f","g","h","i"] 

和一个元组列表:

test2 = [("c",1),("g",1),("b",1),("e",1),("g",1),("d",10),("a",10)] 

我需要排序:

[val for (key, val) in test2] 

并且当 val 与 test1 排序的相同 val 相等时:

test3 = [("b",1),("c",1),("e",1),("f",1),("g",1),("a",10),("d",10)] 

请您参考如下方法:

sorted接受可选参数 key。使用函数的返回值(每个项目都传递给函数)而不是项目本身。

>>> test1 = ["a","b","c","d","e","f","g","h","i"] 
>>> test2 = [("c",1),("g",1),("b",1),("e",1),("g",1),("d",10),("a",10)] 
>>> sorted(test2, key=lambda x: (x[1], test1.index(x[0]))) 
[('b', 1), ('c', 1), ('e', 1), ('g', 1), ('g', 1), ('a', 10), ('d', 10)] 

鉴于上述关键函数顺序将首先按数字，然后在 test1 中定位。