这是我的代码:
def boba_recs(lat, lng):
f1 = pd.read_csv("./boba_final.csv")
user_loc = Point(lng, lat) # converts user lat/long to point object
# makes dataframe of distances between each boba place and the user loc
f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)]
# grabs the three smallest distances
boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name
return(": " + boba['Address'])
返回:
Name
Coco Bubble Tea : 129 E 45th St New York, NY 10017
Gong Cha : 75 W 38th St, New York, NY 10018
Smoocha Tea & Juice Bar : 315 5th Ave New York, NY 10016
Name: Address, dtype: object
几乎完美，只是我想去掉“Name: Address, dtype: object”行。我已经尝试了一些东西，它不会在不弄乱其他所有内容的格式的情况下消失。
请您参考如下方法:
'Address' 是 pd.Series 的名称，'Name' 是索引的名称
尝试:
s.rename_axis(None).rename(None)
Coco Bubble Tea : 129 E 45th St New York, NY 10017
Gong Cha : 75 W 38th St, New York, NY 10018
Smoocha Tea & Juice Bar : 315 5th Ave New York, NY 10016
dtype: object
或者我重写你的函数
def boba_recs(lat, lng):
f1 = pd.read_csv("./boba_final.csv")
user_loc = Point(lng, lat) # converts user lat/long to point object
# makes dataframe of distances between each boba place and the user loc
f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)]
# grabs the three smallest distances
boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name
return(": " + boba['Address']).rename_axis(None).rename(None)
如果你想要一个字符串
def boba_recs(lat, lng):
f1 = pd.read_csv("./boba_final.csv")
user_loc = Point(lng, lat) # converts user lat/long to point object
# makes dataframe of distances between each boba place and the user loc
f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)]
# grabs the three smallest distances
boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name
temp = (": " + boba['Address']).rename_axis(None).__repr__()
return temp.rsplit('\n', 1)[0]
