python之类型错误 : input expected at most1 arguments got 3

嗨，有人可以帮我解释一下哪里出了问题吗？

>Traceback (most recent call last): 
>  File "/Users/admin/Documents/Python Scripts/Stuff I do when bored/Guessing game.py", line >.13, in <module> 
>   guess = int(input("Hi",name,"you will need to guess a number between 1-10")) 
>TypeError: input expected at most 1 arguments, got 3 

代码

import random 
 
 
guesses_taken = 0 
 
print("Welcome to the number guessing game") 
name = input("Hi what is your name?") 
random_number = random.randint(1,10) 
 
 
 
while guesses_taken < 3: 
    guess = int(input("Hi",name,"you will need to guess a number between 1-10")) 
    if guess in random_number: 
        print("Well done you guessed it correctly!") 
        exit() 
 
    elif guess not in random_number: 
        guesses_taken = guesses_taken + 1 
        print("Unlucky! Try again!") 
 
if guesses_taken >= 3: 
    print("Unlucky! Guess it's game over now!") 
    exit() 

请您参考如下方法:

你可以使用字符串的.format方法:

"Hi, {}, you will need to guess a number between 1-10".format(name) 

问题是您向 input() 函数提供以逗号分隔的值。这告诉函数将这些值作为单独的参数。由于 input 只接受一个参数(提示)，因此会引发错误。