python之如何在 python3.3 中使 range() 只有偶数

我是 python 的新手，我想知道是否有一种方法可以编辑 range(100) 以便去掉所有奇数？我正在尝试制作一个简单的“游戏”，您可以在其中想到一个数字，它会告诉您进行一些简单的数学运算，然后告诉您剩下的数字是多少，目前它运行良好，除非它返回一个奇数最后剩下 .5(这不是主要问题，但我宁愿删除它以使其更简单一些)。这是我目前拥有的:

import random, time 
 
numList = range(100) 
 
def getRandomNumber(numList): 
    numIndex = random.randint(0, len(numList) - 1) 
    return numList[numIndex] 
 
def restartProg(): 
    print('Do you want to restart? (Y/N)') 
    return input().lower().startswith('y')   
 
secretNumber = getRandomNumber(numList) 
secretNumber = str(secretNumber) 
answer = int(secretNumber)/2 
answer = str(answer) 
 
while True: 
    print() 
    print('Think of a number between 1 and 100.') 
    time.sleep(3) 
    print() 
    print('Now double that number.') 
    time.sleep(3) 
    print() 
    print('Add ' + secretNumber + ' to it.') 
    time.sleep(6) 
    print() 
    print('Now divide it by 2.') 
    time.sleep(6) 
    print() 
    print('And finally, take away the first number you thought of.') 
    time.sleep(5) 
    print() 
    print('Got it?') 
    time.sleep(5) 
    print() 
    print('The number you are left with is... ' + answer + ', right?') 
    print() 
    print() 
    time.sleep(2) 
 
    gameDone = True 
 
    if gameDone: 
        if restartProg(): 
            secretNumber = getRandomNumber(numList) 
            secretNumber = str(secretNumber) 
            answer = int(secretNumber)/2 
            answer = str(answer) 
            gameDone = False 
        else: 
            break 

请您参考如下方法:

使用 range 的三参数形式-- 第三个参数是步长:

range(0, 100, 2)