while answer == 'Y':
roll = get_a_roll()
display_die(roll)
if roll == first_roll:
print("You lost!")
amount_won = roll
current_amount = amount_earned_this_roll + amount_won
amount_earned_this_rol = current_amoun
print("You won $",amount_won)
print( "You have $",current_amount)
print("")
answer = input("Do you want to go again? (y/n) ").upper()
if answer == 'N':
print("You left with $",current_amount)
else:
print("You left with $",current_amount)
这里使用此循环的目的是在游戏中掷骰子，并且根据掷骰的次数获得奖励，除非您掷的骰子与第一次掷骰相匹配。现在，如果发生这种情况，我需要循环停止，而且我知道这很容易使用 break 语句实现，但是，我被告知不允许使用 break 语句。如果 roll == first_roll，我还能如何让循环终止？
请您参考如下方法:
您可以:
使用标志变量；您已经在使用一个，只需在此处重复使用即可:
running = True while running: # ... if roll == first_roll: running = False else: # ... if answer.lower() in ('n', 'no'): running = False # ...从函数返回:
def game(): while True: # ... if roll == first_roll: return # ... if answer.lower() in ('n', 'no'): return # ...引发异常:
class GameExit(Exception): pass try: while True: # ... if roll == first_roll: raise GameExit() # ... if answer.lower() in ('n', 'no'): raise GameExit() # ... except GameExit: # exited the loop pass
