python之计算由空格分隔的未指定数量的整数并使用字典查找 python 中每个数字的出现次数

示例输出

Enter numbers separated by spaces :1 2 3 3 2 2 2 1 3 4 5 3 
 
{'1': 2, '3': 4, '2': 4, '5': 1, '4': 1} 
 
1 occurs 2 times 
 
3 occurs 4 times 
 
2 occurs 4 times 
 
5 occurs one time 
 
4 occurs one time 

So I'm a total newbie at python but I was thinking of starting off like this :

d = {}      
user = input("Enter numbers separated by spaces :")  
data = user.split()  

除了我尝试过的每个循环都一直说我不能将 str() 转换为 int()，如果有任何帮助，我将不胜感激，我已经盯着这个问题看了几个小时了..这是我尝试过的输入是字符串，试图为字典实现类似的东西

def countdigits (aString):   
  c = 10 * [0] 
 
  for e in aString:  
    c[int(e)] += 1  
 
  return c  
 
def main ():  
  n = 0  
 
  for v in (countdigits(str(input('Enter a string: ')))):  
    if v == 1:  
      print(n, "occurs 1 time") 
    elif v!=0: 
      print(n, "occurs", v, "times") 
 
    n += 1  
 
main() 

对于给定的输出(但使用字典)，我想要一个类似的解决方案

请您参考如下方法:

尝试

d = {i:data.count(i) for i in data} 
 
for k,v in d: 
    print "{0} occurs {1} times\n".format(k,v) 

或喜欢以下评论中的示例:

import collections 
 
for a,b in collections.Counter(data).items(): 
    print "{0} occurs {1} times\n".format(a,b)