python之按线型对线进行分组

我有一个包含如下行的文件:

saldkfjaslk 
    asdlkfja 
    alsdkfjlk 
aslkda;kdfsdlkfaj 
sladkfjalskdfjlaskd 
    sldkfaj 
    lsadkfj 
qwewrewst 
se0polkjlkj 
lpoerlwoej 
    alskdjf 
    asldkfjljlkjlk 
sadlkfa 

我想将以字符(而非空格)开头的行与以空格开头的相应行组合在一起。我还想省略下一行不以空格开头的行。使用上述示例的所需输出如下所示:

[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'), 
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'), 
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')] 

我如何用 Python 解析这个文件？

请您参考如下方法:

>>> regex = re.compile(r"^\S.*(?:\n\s.*)+", re.MULTILINE) 
>>> [tuple(match.split()) for match in regex.findall(s)] 
[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'),  
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'),  
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')] 

解释:

^    # Start of line 
\S   # Match a non-whitespace character 
.*   # Match the rest of the line 
(?:  # Match... 
 \n  #  a newline character 
 \s  #  a whitespace character 
 .*  #  and the rest of the line 
)+   # once or more