python之我希望能够动态地向 python 类添加函数，而事先不知道它们的名称

假设我有一个名字列表。我希望能够将这些作为实例函数动态地添加到类实例中。我知道 types.MethodType 但我是从那里到这里的新手。基本上我想做的是:

class foo( object ): 
     def __init__(self): 
         pass 
 
f = foo() 
names = ["a","b","c"] 
for name in names: 
    add name() to f  # not sure what to do here 
    # what I wanted added to instance "f" is this for each name: 
    def name(self, *args, **kwargs): 
        print( "My name is %s" % inspect.stack()[0][3]   )        
        print( "__called, args=%r, **kwargs=%r" % (args, kwargs) ) 
 
f.a() # ==> calls f.a() 
f.b(1,2,3) # calls f.b(1,2,3 )and so on 

请您参考如下方法:

如果将函数创建为嵌套函数会更容易； name 是从嵌套范围中获取的变量:

import types 
def buildMethod(name, instance): 
    def namefunc(self, *args, **kwargs): 
        print "My name is %s" % name 
        print "__called, args=%r, **kwargs=%r" % (args, kwargs) 
    namefunc.__name__ = name 
    setattr(instance, name, types.MethodType(namefunc, instance, type(instance))) 
 
f = foo() 
names = ["a","b","c"] 
for name in names: 
    buildMethod(name, f) 

这导致:

>>> f.a 
<bound method instance.a of <__main__.foo instance at 0x100d8e560>> 
>>> f.a.__name__ 
'a' 
>>> f.a() 
My name is a 
__called, args=(), **kwargs={} 
>>> f.b() 
My name is b 
__called, args=(), **kwargs={} 
>>> f.c() 
My name is c 
__called, args=(), **kwargs={}