python之替换通过复制转义的字符的最pythonic方法是什么

我正在寻找一个 pythonic 和高效的替代品来替代以下不言自明的代码:

term = "< << >" # turn this into "( < )" 
term.replace("<<", "#~").replace(">>", "~#").replace(">", ")").replace("<", "(").replace("#~", "<").replace("~#", ">") 

有什么想法吗？

请您参考如下方法:

使用正则表达式:

import re 
d = {'<': '(', '>': ')'} 
replaceFunc = lambda m: m.group('a') or d[m.group('b')] 
pattern = r"((?P<a><|>)(?P=a)|(?P<b><|>))" 
term = "< << >" 
 
replaced = re.sub(pattern, replaceFunc, term) #returns "( < )" 

编辑。

上面的正则表达式相当于匹配:

("<<" OR ">>") OR ("<" OR ">") 
 
(?P<a><|>) #tells the re to match either "<" or ">", place the result in group 'a' 
(?P=a) #tells the re to match one more of whatever was matched in the group 'a' 
(?P<b><|>) #tells the re to match a sing "<" or ">" and place it in group 'b' 

确实，lambda 函数 replaceFunc简单地重复这个匹配序列，但返回相关的替换字符。

这re匹配“最大组优先”，所以 "<<< >"将转换为 "<( )" .