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python之Pandas :条件列创建

2025年05月04日20xxx_UU

我正在尝试根据 A 列和 B 列中的值创建 C 列,并满足以下条件:

if A < 5000: C = A * B 
else: C = A 

下面给出语法错误:

df['C'] = df.apply(lambda x (x['A'] * x['B)'] if x['A'] < 5000 else x = x['A']),axis=1) 

我离你有多远?

请您参考如下方法:

使用矢量化 numpy.where :

df['C'] = np.where(df['A'] < 5000, df['A'] * df['B'], df['A']) 

性能:

np.random.seed(2019) 
 
N = 1000 
data = np.asarray([np.random.rand(N).tolist(), list(range(N))]).T 
df = pd.DataFrame(data, columns=['A', 'B']) 
 
In [56]: %timeit df['C'] = np.where(df['A'] < 5000, df['A'] * df['B'], df['A']) 
536 µs ± 47.3 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each) 
 
In [57]: %timeit df['C'] = df.apply(lambda x: x.A * x.B if x.A > 0.5 else x.A, 1) 
30.9 ms ± 597 µs per loop (mean ± std. dev. of 7 runs, 10 loops each) 

N = 100000 
data = np.asarray([np.random.rand(N).tolist(), list(range(N))]).T 
df = pd.DataFrame(data, columns=['A', 'B']) 
 
In [59]: %timeit df['C'] = np.where(df['A'] < 5000, df['A'] * df['B'], df['A']) 
1.29 ms ± 23.9 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each) 
 
In [60]: %timeit df['C'] = df.apply(lambda x: x.A * x.B if x.A > 0.5 else x.A, 1) 
3.32 s ± 374 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)