python之使用破折号组合两个单独列表中的单独元素_编程设计

此程序与预期功能一起使用

使用用户输入创建一个列表以生成五个名称，
使用用户输入创建一个列表，以数字形式生成五个分数/等级。
创建第三个列表，将列表中的每个元素组合在一起第一个列表在第二个列表中具有相应的索引位置。

例如:

Student_Names= [] 
Marks= [] 
StudentNames_Marks= [] 
for i in range (5): #Go through and append the student names into Student_Names list by requesting the information five times and appending each time 
    _name= input("Please enter a name for the student records list. ") 
    Student_Names.append(_name) 
_sum=0 #This is used to create a second for loop under the event that they do not enter a digit within the first list, allowing them to continue forward 
for i in range (5): 
    _marks= input("Please enter marks in digit format. ") 
    if _marks.isalpha(): 
        print("Please enter a digit, such as 10 instead of ten.") 
        _sum=_sum+1 #Add one to the sum to create the amount of loops in the second for loop 
    else: 
        Marks.append(_marks) 
if _sum>0: 
    for i in range(_sum): 
        _marks=input("Please enter marks in digit format. ") 
        if _marks.isalpha(): 
            print("Please enter a digit, such as 10 instead of ten. The program will not run properly. Please restart the program.") 
        else: 
            Marks.append(_marks) 
_numbera= len(Student_Names) #Using the lengths of the list to determine the length of the for loop 
_numberb= len(Marks) 
_length= _numbera+_numberb 
for i in range (5): 
    _value=Student_Names.pop() 
    StudentNames_Marks.append(_value) 
    _value=Marks.pop() 
    StudentNames_Marks.append(_value) 
 
print(StudentNames_Marks)

如果在提示中输入以下内容，则将在控制台上生成以下内容:

Name prompt responses: James, Jack, Ivy, Eva, Lee Marks: 10, 64, 36, 86, 35 Student_Names= ['James', 'Jack', 'Ivy', 'Eva', 'Lee'] Marks= ['10', '64', '36', '86', '35'] StudentNames_Marks= ['Lee', '35', 'Eva', '86', 'Ivy', '36', 'Jack', '64', 'James', '10'

但是，我坚持开发最后一步。我目前已经得到一个列表，它以正确的顺序从前两个列表中获取元素，如上所述。我不确定如何使用破折号组合最终列表中的元素，所以它看起来更像这样:

StudentNames_Marks= ['Lee- 35', 'Eva- 86', 'Ivy- 36', 'Jack- 64', 'James- 10']

我该如何着手做这样的事情？

请您参考如下方法:

使用 zip 和 list comprehension 的一行代码:

>>> ['-'.join(ele) for ele in zip(student_names, marks)]

在这里，zip 命令用于创建组合 student_name 和 marks 的元组，然后使用 join< 将它们连接在一起 函数。

#驱动程序值:

IN : student_names= ['James', 'Jack', 'Ivy', 'Eva', 'Lee'] 
IN : marks = ['10', '64', '36', '86', '35'] 
OUT : ['James-10', 'Jack-64', 'Ivy-36', 'Eva-86', 'Lee-35']