我有一个简单的网站,用户可以在其中注册以访问私有(private)内容并接收时事通讯。我用过django-registration用于用户注册和身份验证,并使用了来自 here 的一些 HTML 模板.
整个系统都在工作(登录、注销、密码恢复等),但我意识到用户无法从网站上删除他们的帐户。是否有为此设计的插件,或者如何扩展注册类来做到这一点?通过删除,我更喜欢真正的抑制,而不仅仅是让用户不活跃。
请您参考如下方法:
你可以这样做:
def delete_user(request, username):
context = {}
try:
u = User.objects.get(username=username)
u.delete()
context['msg'] = 'The user is deleted.'
except User.DoesNotExist:
context['msg'] = 'User does not exist.'
except Exception as e:
context['msg'] = e.message
return render(request, 'template.html', context=context)
并且有一个像这样的 url 模式:
url(r'^delete/(?P<username>[\w|\W.-]+)/$', views.delete_user, name='delete-user')
这将完成工作。它将通过给定的用户名删除用户。
但是,如the docs说:
is_activeBoolean. Designates whether this user account should be considered active. We recommend that you set this flag to
Falseinstead of deleting accounts; that way, if your applications have any foreign keys to users, the foreign keys won’t break.
将用户设置为非事件而不是将其从数据库中完全删除是更好的方法,因为外键会损坏。
所以你可以简单地做:
def delete_user(request, username):
context = {}
try:
user = User.object.get(username=username)
user.is_active = False
user.save()
context['msg'] = 'Profile successfully disabled.'
except User.DoesNotExist:
# ...
except Exception as e:
# ...
# ...
现在每个人都可以访问此 View ,您必须添加一些权限。一种直接的方法是覆盖内置的 @user_passes_test 装饰器:
@user_passes_test(lambda u: u.is_staff, login_url=reverse_lazy('login'))
def delete_user(request, username):
# ...
