python之计算完成前剩余的时间

我想知道如何计算示例所需的时间:

Complete a brute force word list.

我知道如何使用时间功能并及时测量， 但问题是我需要找出程序本身需要多长时间...

这是我昨天做的代码

import itertools, math 
import os 
Alphabet = ("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") # Add or remove whatevs you think will be in the password you're cracking (example, [symbols]) 
counter = 1 
CharLength = 1 
range_num = int(raw_input("Enter range: ")) 
stopper = range_num + 1 
filename = "bruteforce_%r.txt" % (range_num) 
f = open(filename, 'a') 
#n_1 = len(Alphabet) 
#n_2 = n_1 - 1 # <-- total useless peice of garbage that could of been great in vurtual life 
#n_3 = '0' * n_2 
#n = '1' + n_3 
x = range_num 
y = len(Alphabet) 
amount = math.pow(y, x) 
total_items = math.pow(y, x) 
for CharLength in range(range_num, stopper): 
    passwords = (itertools.product(Alphabet, repeat = CharLength)) 
 
    for i in passwords: 
        counter += 1 
        percentage = (counter / total_items) * 100 
        amount -= 1 
        i = str(i) 
        i = i.replace("[", "") 
        i = i.replace("]", "") 
        i = i.replace("'", "") 
        i = i.replace(" ", "") 
        i = i.replace(",", "") 
        i = i.replace("(", "") 
        i = i.replace(")", "") 
        f.write(i) 
        f.write('\n') 
        print "Password: %r\tPercentage: %r/100\tAmount left: %r" % (i, int(percentage), amount) 
        if i == '0'* range_num: 
            print "*Done" 
            f.close() 
            exit(0) 
        else: 
            pass 

这是我成功实现的定时器功能

#import winsound # Comment this out if your using linux 
import os  
import time 
from sys import exit 
 
print "This is the timer\nHit CTRL-C to stop the timer\nOtherwise just let         it rip untill the time's up" 
hours = int(raw_input('Enter the hours.\n>>> ')) 
os.system('clear') # Linux 
#os.system('cls')   # Windows 
 
minutes = int(raw_input('Enter the minutes.\n>>> ')) 
os.system('clear') # linux 
#os.system('cls')   # Windows 
 
seconds = int(raw_input('Enter the seconds.\n>>> ')) 
os.system('clear') # Linux 
#os.system('cls')   # Windows 
 
stop_time = '%r:%r:%r' % (hours, minutes, seconds) 
 
t_hours = 00 
t_minutes = 00 
t_seconds = 00 
 
while t_seconds <= 60: 
    try: 
        os.system('clear') # Linux 
        #os.system('cls') # Windows 
        current_time = '%r:%r:%r' % (t_hours, t_minutes, t_seconds) 
        print current_time 
        time.sleep(1) 
        t_seconds+=1 
 
        if current_time == stop_time: 
            print "// Done" 
            #winsound.Beep(500,1000) 
            #winsound.Beep(400,1000) 
            break 
 
        elif t_seconds == 60: 
            t_minutes+=1 
            t_seconds=0 
 
        elif t_minutes == 60: 
            t_hours+=1 
            t_minutes = 00 
 
    except KeyboardInterrupt: 
        print "Stopped at: %r:%r:%r" % (t_hours, t_minutes, t_seconds) 
        raw_input("Hit enter to continue\nHit CTRL-C to end") 
        try: 
            pass 
 
        except KeyboardInterrupt: 
            exit(0) 

现在我只是想不出如何再做一次，而是计算需要多长时间而不是需要多长时间...

请您参考如下方法:

这是我的实现，它以 H:M:S 格式返回耗时、剩余时间和完成时间。

def calcProcessTime(starttime, cur_iter, max_iter): 
 
    telapsed = time.time() - starttime 
    testimated = (telapsed/cur_iter)*(max_iter) 
 
    finishtime = starttime + testimated 
    finishtime = dt.datetime.fromtimestamp(finishtime).strftime("%H:%M:%S")  # in time 
 
    lefttime = testimated-telapsed  # in seconds 
 
    return (int(telapsed), int(lefttime), finishtime) 

例子:

import time 
import datetime as dt 
 
start = time.time() 
cur_iter = 0 
max_iter = 10 
 
for i in range(max_iter): 
    time.sleep(5) 
    cur_iter += 1 
    prstime = calcProcessTime(start,cur_iter ,max_iter) 
    print("time elapsed: %s(s), time left: %s(s), estimated finish time: %s"%prstime) 

输出:

time elapsed: 5(s), time left: 45(s), estimated finish time: 14:28:18 
time elapsed: 10(s), time left: 40(s), estimated finish time: 14:28:18 
time elapsed: 15(s), time left: 35(s), estimated finish time: 14:28:18 
....