我有一个字典如下:
dt = {'2016-12-15 18:12:17': 1, '2016-12-15 17:40:39': 1, '2016-12-15 15:53:42': 1, '2016-12-15 15:51:41': 1, '2016-12-15 15:49:55': 1, '2016-12-15 15:49:54': 1, '2016-12-15 15:48:05': 1, '2016-12-15 15:27:38': 1, '2016-12-15 09:05:03': 1, '2016-12-15 08:43:45': 1, '2016-12-15 07:29:15': 1, '2016-12-15 05:56:58': 1, '2016-12-14 14:33:31': 1, '2016-12-14 14:33:30': 1, '2016-12-14 14:33:29': 1, '2016-12-14 14:33:28': 1, '2016-12-14 13:24:55': 1, '2016-12-14 13:15:51': 1, '2016-12-14 13:05:38': 1, '2016-12-14 12:58:47': 1}
我想根据日期时间键对字典进行排序。
我试过了:
dt = ordereddict.OrderedDict()
但它不工作请帮助。
请您参考如下方法:
将dt中的keys转换成datetime对象，例如，使用 dateutil.parser.parse ,
from dateutil.parser import parse
from collections import OrderedDict
new_d = OrderedDict(sorted(dt.items(), key=lambda x: parse(x[0])))
print(new_d)
'''
OrderedDict([ ('2016-12-14 12:58:47', 1),
('2016-12-14 13:05:38', 1),
('2016-12-14 13:15:51', 1),
('2016-12-14 13:24:55', 1),
('2016-12-14 14:33:28', 1), ('2016-12-14 14:33:29', 1), ('2016-12-14 14:33:30', 1), ('2016-12-14 14:33:31', 1), ('2016-12-15 05:56:58', 1), ('2016-12-15 07:29:15', 1), ('2016-12-15 08:43:45', 1), ('2016-12-15 09:05:03', 1), ('2016-12-15 15:27:38', 1), ('2016-12-15 15:48:05', 1), ('2016-12-15 15:49:54', 1), ('2016-12-15 15:49:55', 1), ('2016-12-15 15:51:41', 1), ('2016-12-15 15:53:42', 1), ('2016-12-15 17:40:39', 1), ('2016-12-15 18:12:17', 1)])
'''
在您的特定情况下，正如@AndreaCorbellini 所指出的，直接对字符串进行排序工作正常，即
new_d = OrderedDict(sorted(dt.items()))
