python之re.search 将 group(1) 选项的结尾放在 group(2) 的开头。我构建正则表达式有什么问题

我正在尝试根据经常出现的字符串将段落解析为数据字段。这是一个例子:

tstStr = 'Locations of performance are California, North Carolina and Pennsylvania, with a Sept. 14, 2017, performance completion date.' 
pperf = '([Ww]ork will be performed [(in)(at)]|[Ll]ocation[(s )\s] of performance [(is)(are)])(.*?)( and (the work )?is expected| with a(.*)completion date)' 
pTest = re.search(pperf, tstStr) 

预期的结果是:

pTest.group(2) 
California, North Carolina and Pennsylvania, 

相反，我得到:

pTest.group(2) 
re California, North Carolina and Pennsylvania, 

我怎么写错了第一组？

谢谢!

请您参考如下方法:

重点是你的 [(is)(are)] 实际上是一个 character class匹配 1 个符号，(、i、s 等。您需要一个非捕获组，(?:is|are ) 匹配 is 或 are 字符序列。

使用像这样的正则表达式

([Ww]ork will be performed (?:in|at)|[Ll]ocations? of performance (?:is|are))\s*(.*?)( and (the work )?is expected| with a(.*)completion date) 

参见 regex demo