目前正在努力使用 Python 登录 Twitter。
Twitter 的登录页面是 here .用户名和密码输入字段的源代码是:
<div class="LoginForm-input LoginForm-username">
<input
type="text"
class="text-input email-input js-signin-email"
name="session[username_or_email]"
autocomplete="username"
placeholder="Phone, email or username"
/>
</div>
<div class="LoginForm-input LoginForm-password">
<input type="password" class="text-input" name="session[password]"
placeholder="Password" autocomplete="current-password">
</div>
因此,当我使用 Selenium 模块在 Python 中编写代码时:
# -*- coding: utf-8 -*-
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("https://twitter.com/login")
elem = driver.find_element_by_name("session[username_or_email]")
elem.clear()
elem.send_keys(username)
elem = driver.find_element_by_name("session[password]")
elem.clear()
elem.send_keys(password)
elem.send_keys(Keys.RETURN)
sleep(delay)
返回的错误:
selenium.common.exceptions.ElementNotVisibleException: Message: Element is not currently visible and so may not be interacted with
有什么帮助吗?谢谢!我已经阅读了其他类似问题的回答,但没有太大帮助。
编辑:
完整错误信息:
Traceback (most recent call last):
File "main.py", line 154, in <module>
main()
File "main.py", line 143, in main
twitterBruteforce(username, wordlist, delay)
File "src/twitterLib.py", line 27, in twitterBruteforce
elem.clear()
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webelement.py", line 88, in clear
self._execute(Command.CLEAR_ELEMENT)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webelement.py", line 457, in _execute
return self._parent.execute(command, params)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 233, in execute
self.error_handler.check_response(response)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.py", line 194, in check_response
raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.ElementNotVisibleException: Message: Element is not currently visible and so may not be interacted with
Stacktrace:
at fxdriver.preconditions.visible (file:///tmp/tmpurkUhr/extensions/fxdriver@googlecode.com/components/command-processor.js:10092)
at DelayedCommand.prototype.checkPreconditions_ (file:///tmp/tmpurkUhr/extensions/fxdriver@googlecode.com/components/command-processor.js:12644)
at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmpurkUhr/extensions/fxdriver@googlecode.com/components/command-processor.js:12661)
at DelayedCommand.prototype.executeInternal_ (file:///tmp/tmpurkUhr/extensions/fxdriver@googlecode.com/components/command-processor.js:12666)
at DelayedCommand.prototype.execute/< (file:///tmp/tmpurkUhr/extensions/fxdriver@googlecode.com/components/command-processor.js:12608)
请您参考如下方法:
您应该尝试使用 WebDriverWait 等待元素可见,然后再与元素交互,如下所示:-
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 10)
user = wait.until(EC.visibility_of_element_located((By.NAME, "session[username_or_email]")))
user.clear()
user.send_keys(username)
pass = wait.until(EC.visibility_of_element_located((By.NAME, "session[password]")))
pass.clear()
pass.send_keys(password)
注意:- 而不是 send_keys(Keys.RETURN) 尝试使用 click() 作为登录按钮元素作为 login_button_element .click() 或在找到这些元素后尝试使用 submit() 作为 form_element.submit() 到表单元素。
