你好,我是编程新手,我正在尝试编写一个代码,从输入中收集信息并确定它是否是一个有效的字母表。
到目前为止,这是我的代码
words = []
word = input('Character: ')
while word:
if word not in words:
words.append(word)
word = input('Character: ')
print(''.join(words),'is a a valid alphabetical string.')
suppose I choose three letters then the output of my code then pressed enter on the fourth,
the code will be:
Character:a
Character:b
Character:c
Character:
abc is a valid alphabetical string.
I want to add to this code so that when I type in a character that is not
from the alphabet the code will do something like this.
Character:a
Character:b
Character:c
Character:4
4 is not in the alphabet.
这就是我希望我的程序运行的方式
请您参考如下方法:
使用str.isalpha() 仅当字符串中的所有字符都是字母时才为真。
例子:
>>> 'test'.isalpha()
True
>>> 'test44'.isalpha()
False
>>> 'test test'.isalpha()
False
在您的代码中:
words = []
word = input('Character: ')
while word:
if word.isalpha() and word not in words:
words.append(word)
word = input('Character: ')
print(words,'is a a valid alphabetical string.')
