我有一个列表，其中包含一些值，每个值后跟一些 Nones:
['Apple', None, None, None, None, None, None, 'Orange', None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, 'Pear', None, None, None, None, None, None, None, 'Banana', None, None]
我想要这样的输出，它将列表分成单独的列表，每个列表都以非 None 值作为断点:
['Apple', None, None, None, None, None, None]
['Orange', None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None]
['Pear', None, None, None, None, None, None, None]
['Banana', None, None]
我正在为如何去做而绞尽脑汁。
请您参考如下方法:
你说你想用最新的非 None 值替换 None。我将跳过“如何拆分”问题，并回答“替换”问题:
def fill_nones(seq):
last = None
for val in seq:
if val is not None:
last = val
yield last
现在您可以创建一个新列表:
filled = list(fill_nones(old_list))
